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WITCHER [35]
3 years ago
7

Solve each proportion. 8/x+9=2/x-3 Please show work.

Mathematics
2 answers:
emmainna [20.7K]3 years ago
7 0


8/x+9-(2/x-3)=0

Step by step solution :


Step 1 :

2
Simplify —
x
Equation at the end of step 1 :

8 2
(— + 9) - (— - 3) = 0
x x
Step 2 :

Rewriting the whole as an Equivalent Fraction :

2.1 Subtracting a whole from a fraction

Rewrite the whole as a fraction using x as the denominator :

3 3 • x
3 = — = —————
1 x
Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

2.2 Adding up the two equivalent fractions
Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

2 - (3 • x) 2 - 3x
——————————— = ——————
x x
Equation at the end of step 2 :

8 (2 - 3x)
(— + 9) - ———————— = 0
x x
Step 3 :

8
Simplify —
x
Equation at the end of step 3 :

8 (2 - 3x)
(— + 9) - ———————— = 0
x x
Step 4 :

Rewriting the whole as an Equivalent Fraction :

4.1 Adding a whole to a fraction

Rewrite the whole as a fraction using x as the denominator :

9 9 • x
9 = — = —————
1 x
Adding fractions that have a common denominator :

4.2 Adding up the two equivalent fractions

8 + 9 • x 9x + 8
————————— = ——————
x x
Equation at the end of step 4 :

(9x + 8) (2 - 3x)
———————— - ———————— = 0
x x
Step 5 :

Adding fractions which have a common denominator :

5.1 Adding fractions which have a common denominator
Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

(9x+8) - ((2-3x)) 12x + 6
————————————————— = ———————
x x
Step 6 :

Pulling out like terms :

6.1 Pull out like factors :

12x + 6 = 6 • (2x + 1)

Equation at the end of step 6 :

6 • (2x + 1)
———————————— = 0
x
Step 7 :

When a fraction equals zero :

7.1 When a fraction equals zero ...
Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

6•(2x+1)
———————— • x = 0 • x
x
Now, on the left hand side, the x cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :
6 • (2x+1) = 0

Equations which are never true :

7.2 Solve : 6 = 0

This equation has no solution.
A a non-zero constant never equals zero.
Vikki [24]3 years ago
6 0

Answer:

x=7

Step-by-step explanation:

8/x+9 = 2/x-3

(8) x-3 = (2) x+9

8x-24 = 2x+18

6x-24=18

6x=42

x=7

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Step-by-step explanation:


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Please help explanation if possible
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Step-by-step explanation:

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3 0
3 years ago
Given: AB ≅ BC , m∠MOC = 135° OM − angle bisector of ∠AOB Prove: ∠ABO ≅ ∠CBO
Gennadij [26K]

Answer:

See explanation

Step-by-step explanation:

1. Angles AOM and MOC are supplementry angles. If m∠MOC = 135°, then

m∠AOM = 180° - 135° = 45°

2. OM − angle bisector of ∠AOB, then

m∠AOM = m∠MOB = 45°

3. Now

m∠BOC = m∠MOC - m∠MOB

m∠BOC = 135° - 45° = 90°

4. Since m∠BOC = 90°, BO is perpendicular to AC.

5. Consider isosceles triangle ABC (because AB ≅ BC). BO is the height drawn to the base, so it is an angle B bisector too, thus

∠ABO ≅ ∠CBO

8 0
2 years ago
A right triangle has legs measuring 18 in. and 26 in. What is the length of the hypotenuse? Round to the nearest tenth. A) 18.8
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Step-by-step explanation:

3 0
3 years ago
An octagonal swimming pool has a base area of 22 square feet The pool is 3 feet deep How many cubic feet of water can the pool h
LenKa [72]

The pool can hold 65.84 ft³ of water

<u>Explanation:</u>

Given:

Shape of pool = octagonal

Base area of the pool = 22 ft²

Depth of the pool = 3 feet

Volume, V = ?

We know:

Area of octagon = 2 ( 1 + √2) a²

22 ft² = 2 ( 1 + √2 ) a²

\frac{11}{1+\sqrt{2} } = a^2

a² = \frac{11}{2.42}

a² = 4.55

a = 2.132 ft

Side length of the octagon is 2.132 ft

We know:

Volume of octagon = 2(1+\sqrt{2} ) X (a)^2 X h

V = 2(1+\sqrt{2})X (2.132)^2 X 3\\ \\V = 2 ( 2.414) X 4.5454 X 3\\\\V = 65.84 ft^3

Therefore, the pool can hold 65.84 ft³ of water

8 0
3 years ago
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