Rewrite the whole as a fraction using x as the denominator :
3 3 • x 3 = — = ————— 1 x Equivalent fraction : The fraction thus generated looks different but has the same value as the whole
Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator
Adding fractions that have a common denominator :
2.2 Adding up the two equivalent fractions Add the two equivalent fractions which now have a common denominator
Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:
2 - (3 • x) 2 - 3x ——————————— = —————— x x Equation at the end of step 2 :
8 (2 - 3x) (— + 9) - ———————— = 0 x x Step 3 :
8 Simplify — x Equation at the end of step 3 :
8 (2 - 3x) (— + 9) - ———————— = 0 x x Step 4 :
Rewriting the whole as an Equivalent Fraction :
4.1 Adding a whole to a fraction
Rewrite the whole as a fraction using x as the denominator :
9 9 • x 9 = — = ————— 1 x Adding fractions that have a common denominator :
4.2 Adding up the two equivalent fractions
8 + 9 • x 9x + 8 ————————— = —————— x x Equation at the end of step 4 :
(9x + 8) (2 - 3x) ———————— - ———————— = 0 x x Step 5 :
Adding fractions which have a common denominator :
5.1 Adding fractions which have a common denominator Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:
(9x+8) - ((2-3x)) 12x + 6 ————————————————— = ——————— x x Step 6 :
Pulling out like terms :
6.1 Pull out like factors :
12x + 6 = 6 • (2x + 1)
Equation at the end of step 6 :
6 • (2x + 1) ———————————— = 0 x Step 7 :
When a fraction equals zero :
7.1 When a fraction equals zero ... Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.
Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.
Here's how:
6•(2x+1) ———————— • x = 0 • x x Now, on the left hand side, the x cancels out the denominator, while, on the right hand side, zero times anything is still zero.
The equation now takes the shape : 6 • (2x+1) = 0
Equations which are never true :
7.2 Solve : 6 = 0
This equation has no solution. A a non-zero constant never equals zero.
Please let me know if you want me to add an explanation as to why this is the answer. I can definitely do that, I just wouldn’t want to write it if you don’t want me to :)
That is false because, this type of system can have one solution, two solutions, or no solutions. Graph both equations on the same coordinate plane. Identify the point of intersection, if any. Hope I Helped : )
