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balu736 [363]
3 years ago
11

A protocol stack is _____.

Computers and Technology
2 answers:
LiRa [457]3 years ago
3 0

Answer:

A protocol stack is a group of protocols that all work together to allow software or hardware to perform a function.

Explanation:

The protocol stack is used to allow the combination of different protocols that each set the boundaries for a number of network activities.

Anna11 [10]3 years ago
3 0

Answer:

- Layer 5: Application layer

- Layer 4: Transport Layer

- Layer 3: Network Layer

- Layer 2: Data Link Layer

- Layer 1: Physical Layer

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A technician installs a new WAP and users in the area begin to report poor performance. The technician uses a ping and only 3 of
krek1111 [17]

Answer: the correct answer is D. Spectrum Analyzer tool

Explanation:

A spectrum analyzer is a piece of electronic equipment that is used to gauge the magnitude (amplitude or strength) of a given input signal set against the full frequency range of the instrument. It is mainly used to measure the strength of the range of known and unknown signals.

4 0
3 years ago
When configuring the authentication methods for a remote access server, you should select the option Allow remote systems to con
Irina-Kira [14]

Based on the computer technology setup, it is <u>False</u> that when configuring the authentication methods for a remote access server, you should select the option Allow remote systems to connect without authentication.

<h3>What are Remote Access Systems?</h3>

Remote Access Systems is a type of system that can be used to regulate and control access to a computer or network.

Remote Access System or Control can be operated anywhere and anytime.

However, in this case, the correct option to pick is "Allow DirectAccess Only." This option will allow a user to connect without authentication.

<h3>Deploying Remote Access from the Remote Access Management console</h3>

There are three methods upon which one can deploy remote access; these methods include the following:

  • DirectAccess and VPN
  • DirectAccess only
  • VPN only

Hence, in this case, it is concluded that the correct answer is False.

Learn more about Remote Access Systems here: brainly.com/question/24339774

3 0
2 years ago
Difference between sorting and filtering​
Serggg [28]
<h3>Sorting</h3>

The term “sorting” is used to refer to the process of arranging the data in <u>ascending or descending order</u>.

Example: Statistical data collected can be sorted alphabetically or numerically based on the value of the data.

<h3>Filtering</h3>

The process of data filtering involves selecting a <u>smaller part of your data set to view or analyze</u>. This is done by using that subset to view or analyze your data set as a whole.

Example: A complete set of data is kept, but only a portion of that set is used in the calculation, so the whole set is not used.

<em>Hope this helps :)</em>

5 0
1 year ago
Read 2 more answers
Create an interface MessageDecoder that has a single abstract method decode(cipherText), where cipherText is the message to be d
Nastasia [14]

Answer:

Check the explanation

Explanation:

MessageEncoder. java

public interface MessageEncoder

{

  //single abstract method encode(plainText) where plainText is the message to be encoded.

  public String encode(String plainText);

}//end interface

SubstitutionCipher. java

import java.util.Scanner;

public class SubstitutionCipher implements MessageEncoder, MessageDecoder

{

   /**

     The constructor should have 1 parameter called shift

   */

   private int shift;

 

   /**

     Non-default constructor with one parameter    

   */

   public SubstitutionCipher(int numberSpaces)

   {

       shift = numberSpaces;

   }//end non default constructor

 

   /**

     Define the method encode so that each letter is shifted by the value in shift

   */

   public String encode(String plainText)

   {

       String cipherText = "";

       for(int i = 0; i < plainText. length(); i++)

       {

           Character encodeLetter = plainText.charAt(i);

           cipherText = cipherText + shift1Character(encodeLetter);

       }//end for loop

       return cipherText;

   }//end encode method

 

   /**

     Define the method decode so that each letter is shifted by minus the value in shift

   */

   public String decode(String cipherText)

   {

       String plainText = "";

       for(int i = 0; i < cipherText. length(); i++)

       {

           Character decodeLetter = cipherText.charAt(i);

           plainText = plainText + shift1CharacterBack(decodeLetter);

       }//end for loop

       return plainText;

   }//end encode method

   /**

     Hint: You may wish to define a private method that shifts a single character

   */

   private Character shift1Character(Character oneLetter)

   {

       return (char)(oneLetter + shift);

   }//end method

 

   /**

     Hint: You may wish to define a private method that shifts a single character

           back to its original position

   */

   private Character shift1CharacterBack(Character oneLetter)

   {

       return (char)(oneLetter - shift);

   }//end method

 

////////////////////////////////////////////////////////////////////////////////////////////////////////

   public static void main(String[] args)

   {

       Scanner keyboard = new Scanner(System.in);

       SubstitutionCipher shift3Places = new SubstitutionCipher(3);

       System.out.println("Substituation method using caesar shift: \n");

       String plainText = "I think I am finally back on track\n";

       System.out.println("Plain text to be encoded: " + plainText);

     

       String cipher = shift3Places.encode(plainText);

       System.out.println("Cipher text after encoding: " + cipher);

     

       SubstitutionCipher shiftMinus3 = new SubstitutionCipher(-3);

       System.out.println("\n\nTime to decode the cipher now.\n");

     

       String decoded = shiftMinus3. encode(cipher);

       System.out.println("Decoded text after removing cipher: " + decoded);

   

       ////////////////////////////////////////////////////////////////////////////System.out.println("Testing the decode method.");

       ////////////////////////////////////////////////////////////////////////////decoded = shift3Places. decode(cipher);

       ////////////////////////////////////////////////////////////////////////////System.out.println("Text after decoding: " + decoded);

   }//end main

}//end class

MessageDecoder. java

public interface MessageDecoder

{

  //single abstract method decode(cipherText) where cipherText is the message to be decoded.

  public String decode(String cipherText);

}//end interface

3 0
3 years ago
Does out-of-order makea machine's performance more or less
irina1246 [14]

Answer:

It would be correct to say that out-of-order makes a machine's performance more sensitive to branch prediction accuracy.

Explanation:

This can be explained as when a machine is out-of-order, in that state the  execution holds importance in prediction accuracy, any increase in these results in rate of prediction near about 25% for the single-issue operating in-order. This is due to the reason that some of the predictions are required for the global pattern history. Most recent outcomes are recorded in the register and for a 4-way machine which is out-of-order, accuracy is very poor as a result of the delay of the branch history for next prediction.

3 0
3 years ago
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