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olasank [31]
3 years ago
8

Refer to the method f: Public int f( int k, int n ) { if( n == k ) return k; else if( n > k ) return f( k, n - k ); else retu

rn f( k - n, n ); } What value is returned by the call f( 6, 8 )?
Computers and Technology
1 answer:
Debora [2.8K]3 years ago
5 0

Answer:

Returned value: 2

Explanation:

Public int f(int k, int n) {

   if (n == k)

       return k;

   else if (n > k)

       return f(k, n - k);

   else return f(k - n, n);

}

/////////////////////////////////////////////////////////////////////////////////////////

Trace of function calls,

f(6, 8)

f(k, n - k) -> (6, 2)

f(k - n, n) -> (4, 2)

f(k - n, n) -> (2, 2)

return k

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Define function print_popcorn_time() with parameter bag_ounces. If bag_ounces is less than 3, print "Too small". If greater than
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Answer:

public static void print_popcorn_time(int bag_ounces){

       if(bag_ounces<3){

           System.out.println("Too Small");

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Explanation:

Using Java prograamming Language.

The Method (function) print_popcorn_time is defined to accept a single parameter of type int

Using if...else if ....else statements it prints the expected output given in the question

A complete java program calling the method is given below

public class num6 {

   public static void main(String[] args) {

       int bagOunces = 7;

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   public static void print_popcorn_time(int bag_ounces){

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           System.out.println("Too Small");

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       else if(bag_ounces>10){

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       else{

           bag_ounces*=6;

           System.out.println(bag_ounces+" seconds");

       }

   }

}

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