All categories

3 years ago

S = ut + 12 at? u= 10 a = -2 t = Work out the value of s.

Mathematics

1 answer:

Stella [2.4K]3 years ago

7 0

S = (10 x1 /2) + (1/2x- 2x 1/2²)
5 + (-0.25)
= 4.75

You might be interested in

Factor completely 4x^2 − 32

Blababa [14]

Answer: $4(x+2\sqrt{2})(x-2\sqrt{2})$

Step-by-step explanation:

We can first take out the common factor of 4, as both 4x² and -32 are divisible by 4.

$4(x^2-8)$

From here, we can assume that x²-8 is a difference of two squares even though 8 is not a perfect square.

<em>For review, a difference of two squares </em> $a^2-b^2$ can be factored into $(a+b)(a-b)$ .

$4(x^2-8)\\4(x+\sqrt{8})(x-\sqrt{8})\\4(x+2\sqrt{2})(x-2\sqrt{2})$

4 0

2 years ago

What is<br> x=3y-1<br> x=-2y+9

-Dominant- [34]

Are you to combine the answer or are they 2 separate equations you need to solve for y?

8 0

3 years ago

Read 2 more answers

5. Is the side that is 100 meters long the hypotenuse, opposite or adjacent side? *

Stolb23 [73]

Answer:

adjacent

Step-by-step explanation:

It is the leg that touches the 18 degree angle

7 0

3 years ago

Solve for : can someone plss help I dont remember how to solve this

ArbitrLikvidat [17]

Answer:

x = 18

Step-by-step explanation:

7x - 26 = 5x + 10

7x - 26 - 5x - 10 =0

2x - 36 = 0

2x = 36

x = 18

7 0

3 years ago

Can anyone please explain? Need some help :)

DedPeter [7]

Answer:

93.5 square units

Step-by-step explanation:

Diameter of the Circle = 12 Units

Therefore:

Radius of the Circle = 12/2 =6 Units

Since the hexagon is regular, it consists of 6 equilateral triangles of side length 6 units.

Area of the Hexagon = 6 X Area of one equilateral triangle

Area of an equilateral triangle of side length s = $\dfrac{\sqrt{3} }{4}s^2$

Side Length, s=6 Units

$\text{Therefore, the area of one equilateral triangle =}\dfrac{\sqrt{3} }{4}\times 6^2\\\\=9\sqrt{3} $ square units$

Area of the Hexagon

$= 6 X 9\sqrt{3} \\=93.5$ square units (to the nearest tenth)$

7 0

3 years ago