The lottery game is an illustration of probability
- The total number of different selections is 1000
- The probability of winning is 0.001
- The net profit of winning is $262.82
- The expected earning is -$1.156
<h3>The number of selections</h3>
Each of the three selections can be any of the 1o digits 0 - 9.
So, the total number of different selections is:
<h3>The probability of winning</h3>
Only one of the 1000 selections can win.
So, the probability of winning is:
<h3>The net profit</h3>
The stake amount is given as $1.42, and the earnings per game is given as $264.25.
So, the net profit is:
Net = $264.25 - $1.42
Net = $262.82
<h3>The expected winnings</h3>
This is calculated as:
So, we have:
Hence, the expected earning is -$1.156
Read more about probability at:
brainly.com/question/25870256
Using the discriminant from the quadratic formula (√b²-4ac) since that is the only way to get a solution to not be real (b²-4ac has to be negative), we get
m²-4*3*7=m²-84. Solving for m if m²-84=0, m²=84 and m=+-√84. Therefore, if m is positive, the highest possible value of m is √84. However, we have to find the integer value - with a bit of guess and check, we find that 9²=81 and is the integer you get by rounding down √84 (if we rounded up, 10 would have real solutions since we need the square to be less than 84 to get m²-84 negative). Therefore, 9 is our answer
If we divide 56 by 4 we get 14. Why by4? So that one number is 3 times the other So he had 14 balls that went into the green bags and 42 (56-14) that went into the red bags. We could just answer the question and say 14 but I think they want to know how many in each green bag.
14 and 42 don't work because they are not the same number of balls. What number is a common factor? 7 is,
We could have 2 green bags and split the 14 balls into 2 groups of 7 and with the remaining 42 - put them into 6 red bags of 7 each.
And so the answer to your question is:
7 ball in each bag = 2 bags are green, and 6 bags are red
14 balls + 42 balls = 56 bouncy balls
