<span>#1 is C
</span><span>#2 is B
</span>3a is On the circle
<span>3b is inside
</span><span>3d is on
</span><span>3e is outside
</span>
<span>4a is "You can find if a triangle is right by using the Pythagorean theorem or by using perpendicular lines"
</span><span>4b): Using the Pythagorean Side AC (which is √10 units long)^2 + side AB (which is √40 units long)^2 is equal to 50 (which is the length of side BC). Using perpendicular lines, you find that line AB has a slope of 1/3 and side AC has a slope of -3. Since these two are opposite reciprocals, they are perpendicular, which means that they form a 90 degree angle.
</span><span>5.) To find the midpoint, use the formula (x2+x1/2,y2+y1/2) by using the given coordinates, we find that the midpoint is (1,-2). This point lies in quadrant IV, so it is proven that it's midpoint lies in quadrant IV.
</span>
:)
Answer:
(p - 3)(q + 1)
Step-by-step explanation:
Rearrange the terms in the expression as
pq - 3q + p - 3 ( factor the first/second and third/fourth terms )
= q(p - 3) + 1(p - 3) ← factor out (p - 3) from each term
= (p - 3)(q + 1) ← in factored form
