<h3>
Answer: 53%</h3>
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Explanation:
The question asks "What percent of females participate in extracurricular activities?" This means we only focus on the second column. There are 36 women, and of this total, 19 are in extracurricular activities.
Dividing the two values leads to approximately 19/36 = 0.52777 which rounds to 0.53
Then we move the decimal to the right two spots to get 53%
Roughly 53% of the female students participate in extracurricular activities.
We can find the midpoint of any line segment using the midpoint formula: M=(x1+x2/2,y1+y2/2). Essentially, the midpoint formula finds the average of two points. If we use B and the first point and C as the second, when we plug in our values we would have M=(5-4/2,9-5/2). This can be simplified to M=(1/2,4/2) or M=(1/2,2) which is the final answer.
<span>I hope this helps.</span>
Step-by-step explanation:
√a = 1√a so we can solve them easily:
b) 3√7 -√7= 3√7 - 1√7 =( 3-1)√7= 2√7
d) 5√6 - 2√6+√6= (5-2+1)√6 = 4√6
g) √2+2√2= 3√2
j) √5+5√5 - 3√5 = 3√5
k) 2√3 + √3 - 5√3= -2√3
I) 5√11 + 7√11 - √11 = 11√11
Answer:
A zoo
Step-by-step explanation:
A zoo can't be consisdered a "service industry" compared to the other ones.
So
A.) Zoo
is your answer
Answer:
(D)3.6 cm esa es amigo buen dia
