Bc has endpoints b(5 ,9) and c(-4, -3). Find the coordinates of the midpoint of bc

Mathematics

2 answers:

Maksim231197 [3]3 years ago

5 0

(1/2 , 3) is the midpoint

Alex73 [517]3 years ago

4 0

We can find the midpoint of any line segment using the midpoint formula: M=(x1+x2/2,y1+y2/2). Essentially, the midpoint formula finds the average of two points. If we use B and the first point and C as the second, when we plug in our values we would have M=(5-4/2,9-5/2). This can be simplified to M=(1/2,4/2) or M=(1/2,2) which is the final answer.

<span>I hope this helps.</span>

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earnstyle [38]

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We'll manipulate the expression of the equation:

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Then, the function has one real zero (x=3) and two imaginary zeros (4i and -4i).

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• Second way to solve:

The degree of the function is 3. So, the function has 3 complex zeros.

Since the coefficients of the function are reals, the imaginary roots are in a even number (a imaginary number and its conjugated)

The function "has only one non-repeated x-intercept", then there is only one real zero.

The number of zeros is 3 and there is 1 real zero. So, there are 2 imaginary zeros.

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