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Nastasia [14]
2 years ago
6

If 2k - 3 = 9 (k+7)-3 then k is ????

Mathematics
2 answers:
Akimi4 [234]2 years ago
6 0

Answer:

K = -9

Step-by-step explanation:

2k-3 = 9(k+7)-3

2k-3 = 9k+63-3

2k-3 = 9k+60

2k-9k = 60+3

-7k = 63

-k = 9

k = -9

m_a_m_a [10]2 years ago
4 0

Answer:

k= -9

Step-by-step explanation:

2k-3=9k+63-3     [expand the 9(k+7) first]

2k-9k=63-3+3     [put the like terms together]

-7k=63                 [do the simple math]

k= 63 ÷ by -7

k=-9  

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6 0
3 years ago
20 POINTS HELPPPPP
kiruha [24]

For this case we have the following expression:

\frac {216 ^ {n-2}} {(\frac {1} {36}) ^ {3n}} = 216

We multiply both sides by: (\frac {1} {36}) ^ {3n}

216 ^ {n-2} = 216 * (\frac {1} {36}) ^ {3n}

We divide both sides by 216:

\frac {216 ^ {n-2}} {216} = (\frac {1} {36}) ^ {3n}

To divide powers of the same base, we place the same base and subtract the exponents:

216 ^ {n-2-1} = (\frac {1} {36}) ^ {3n}\\216 ^ {n-3} = (\frac {1} {36}) ^ {3n}

Rewriting:

(6 ^ 3) ^ {n-3} = (\frac {1} {6 ^ 2}) ^ {3n}\\6 ^ {3n-9} = \frac {1} {6 ^ {6n}}\\6^{ 3n-9} * 6^{ 6n} = 1

To multiply powers of the same base, we place the same base and add the exponents:

6^{ 3n-9 + 6n} = 1\\6^{ 9n-9} = 1

We know that any number raised to zero is 1, a ^ 0 = 1.

So, for equality to be true:

9n-9 = 0\\9n = 9\\n = \frac {9} {9}\\n = 1

Answer:

n = 1

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Step-by-step explanation:


6 0
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Please help me with this question!!!!!
amm1812

Answer:

B. H(x)=-.008(x-82)^{2}+83

Step-by-step explanation:

Well lets graph the following equation first,

H(x) = -.011(x - 82)^2 + 75

Then lets graph all the other equations.

Look at the image below↓

So A.

The purple line does not go farther or higher,

so A. is incorrect

B.

The black line goes higher and farther,

meaning it is correct.

C.

The red line goes farther but not higher.

So it is incorrect

D.

Again the blue line does not go farther of higher.

So its wrong.

<em>Thus,</em>

<em>answer choice B. </em>H(x)=-.008(x-82)^{2}+83 <em>is correct.</em>

<em />

<em>Hope this helps :)</em>

3 0
3 years ago
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