Try this option:
1. for vertex (2;1) the first equation is: h=-b/2a, it means 2=-b/2a or b=-4a;
2. for vertex (2;1) the second equation is: ax²+bx+c=y, it means 1=4a+2b+c;
3. for point (6;7) the third equation is: ax²+bx+c=y, it means 7=36a+6b+c.
4. using three equation, it is possible to make up the system of equations (and solve it). Details are in the attached picture.
answer:
![y= \frac{3}{8}x^2 - \frac{3}{2}x + \frac{5}{2}](https://tex.z-dn.net/?f=y%3D%20%5Cfrac%7B3%7D%7B8%7Dx%5E2%20-%20%5Cfrac%7B3%7D%7B2%7Dx%20%2B%20%5Cfrac%7B5%7D%7B2%7D%20)
The graph is in the attachment.
the assumption being, that the angles at vertices C and B are right-angles, namely 90°, which will mean that C and B are points of tangency, since tangent lines and radius segments always meet at right-angles.
well, the tangents lines meet outside at a certain point, here at vertex A, when that happens, both outside tangents are the same length, so AB = 6 = AC.
8c = 14 - 5c - 1
13c = 13
c = 1
Uhmm what are you asking..?
The common ratio in the geometric sequences 2
<span />