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slava [35]
3 years ago
12

In QRS m Q = 80 degrees m R = 65 degrees m S = 35 degrees which side of the QRS is the longest

Mathematics
1 answer:
lutik1710 [3]3 years ago
7 0

Answer: RS

Step-by-step explanation:

A greater angle of a triangle is opposite a greater side. If angle Q is greater than angle R, then side RS is greater than side QS.

Because Q is the larger angle in the triangle, Then RS is the longest side.

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-5s=−13<br> solve for s .
Marizza181 [45]

Answer:

The answer is going to be 13/5 or 2.6

Step-by-step explanation:

You are going to need to divide both sides by the constant of -5 in order to get s by itsef. After you divide both sides by -5, you will get -13/-5 which two negatives divided by a positive so it would be 13/5 or if you turn it into an integer, it would be 2.6

7 0
3 years ago
0.22/m = 0.05/3.7 please could you answer
Maslowich

Answer:

16.28

Step-by-step explanation:

0.22/m=0.05/3.7

0.814/0.05=m

m=16.28

6 0
4 years ago
Read 2 more answers
Multiple choice answers:<br><br> A. 1/2<br> B. 2<br> C. -2<br> D -1/2
Katarina [22]

Answer:

c

Step-by-step explanation:

rise over run

goes down 2

goes to the right one

-2/1=-2

6 0
3 years ago
Please help
djyliett [7]

Answer:

x+6<12

Step-by-step explanation:

Since it is going left from 6, we know that x must be less than 6

(if u need me to explain more I can)

8 0
3 years ago
Read 2 more answers
Henrietta is planting a new flower garden she must have yellow and red rose bushes let X represent the number of yellow rose bus
salantis [7]

Answer:

x \geq 4y

7.50x+4.75y\leq 125

x > 0

y > 0

Step-by-step explanation:

Let

x -----> the number of yellow rose bushes

y -----> the number of red rose bushes

we know that

At least means "greater than or equal to"

x \geq 4y ----> inequality A

7.50x+4.75y\leq 125 -----> inequality B

additionally

The number of roses cannot be a negative number

so

x > 0 ----> inequality C

y > 0 ----> inequality D

therefore

The restraints are

x \geq 4y

7.50x+4.75y\leq 125

x > 0

y > 0

5 0
3 years ago
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