The height is 5 m. The area of a trapezoid is (b1+b2/2)h
y= 3/8 OR 0.375
Step-by-step explanation:
yes
Answer:
<h2><DEF = 40</h2><h2><EBF = <EDF = 56</h2><h2><DCF = <DEF =40</h2><h2><CAB = 84</h2>
Step-by-step explanation:
In triangle DEF, we have:
<u>Given</u>:
<EDF=56
<EFD=84
So, <DEF =180 - 56 - 84 =40 (sum of triangle angles is 180)
____________
DE is a midsegment of triangle ACB
( since CD=DA(given)=>D is midpoint of [CD]
and BE = EA => E midpoint of [BA] )
According to midsegment Theorem,
(DE) // (CB) "//"means parallel
and DE = CB/2 = FB =CF
___________
DEBF is a parm /parallelogram.
<u>Proof</u>: (DE) // (FB) ( (DE) // (CB))
AND DE = FB
Then, <EBF = <EDF = 56
___________
DEFC is parm.
<u>Proof</u>: (DE) // (CF) ((DE) // (CB))
And DE = CF
Therefore, <DCF = <DEF =40
___________
In triangle ACB, we have:
<CAB =180 - <ACB - <ABC =180 - 40 - 56 =84(sum of triangle angles is 180)

Answer:
1.) Triangle is <u>1/2 x b x h (Which is option C)</u>
2.) Rhombus is<u> ½ × d1 × d2. (Which is option A)</u>
3.) Trapezoid is <u>½(b 1+b 2)h or (b1 + b2)h/2 (Which is option B)</u>
4.) Parallelogram is <u>base x height (Which is option D)</u>
Step-by-step explanation:
Answer:

Step-by-step explanation:

(Add 25 to both sides)
( Take square of both sides)


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