Answer:
Carl has 35 dimes and 90 quarters
Step-by-step explanation:
Let the number of quarters be q and the number of dimes be d
Total number of coins is 125;
Hence;
q + d = 125 •••••••••(i)
The total value of quarters present = q * 0.25 = 0.25q
The total value of dimes present = d * 0.1 = 0.1d
Adding both gives the total
0.25q + 0.1d =26 ••••••••(ii)
So we need to solve both equations simultaneously;
From i,
q = 125 - d
Substitute this into ii
0.25(125-d) + 0.1d = 26
31.25 -0.25d + 0.1d = 26
31.25 -26 = 0.25d -0.1d
5.25 = 0.15d
d = 5.25/0.15
d = 35
Recall; q = 125 - d = 125 -35 = 90
Answer: option D is the correct answer.
Step-by-step explanation:
The given sequence is a geometric sequence because the consecutive terms differ by a common ratio.
The formula for determining the nth term of a geometric progression is expressed as
an = a1r^(n - 1)
Where
a1 represents the first term of the sequence.
r represents the common ratio.
n represents the number of terms.
From the information given,
a1 = 36
r = 12/36 = 4/12 = 1/3
Therefore, the formula for the nth term of the sequence is
an = 36 × 1/3^(n - 1)
an = 36 × 3^-1(n - 1)
an = 36 × 3^(-n + 1)
an = 36 × 3^(1 - n)
The answer as a fraction is 14/15
Answer:
5
Step-by-step explanation:
We can express 125 as 5 x 5 x 5. Therefore, the value of the cube root of 125 is 5.
![\sqrt[3]{125} = \sqrt[3]{5 \times 5 \times 5} = 5](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B125%7D%20%20%3D%20%20%5Csqrt%5B3%5D%7B5%20%5Ctimes%205%20%5Ctimes%205%7D%20%20%3D%205)
y<-14/3 is the answer
Step 1: Simplify both sides of the inequality.
−3y+2>16
Step 2: Subtract 2 from both sides.
−3y+2−2>16−2
−3y>14
Step 3: Divide both sides by -3.
−3y
−3
>
14
−3
y<
−14
3
