Answer:
Step-by-step explanation:
Begin by grouping the x terms and the y terms together and separating the constants out.

Now we'll complete the square on those x and y terms. Take half the linear term of each, square it, and add it to both sides. Our linear x term is 2, half of 2 is 1 and 1 squared is 1, so we add that in. Likewise, half the linear y term (which is 8) is 4, and 4 squared is 16, so we add that in, too. Like this:

Doing this gives us the perfect square binomials for each of the x and y terms, and then gives us the radius on the right:

This is a circle with a center of (1, 4) and a radius of 3.
In the figure, ABCD is a trapezoid with legs AB and CD.
Join AC and BD.
For the triangle CAD, from the vertex C, draw an altitude CE and for the triangle ABD, from the vertex B, draw an altitude BF.
Clearly, CE = BF = h (say) --- (1)
Note that the base of the triangles CAD and ABD are the same and is AD.
It is given that ar(CAD) =
.
Now, ar(ABD) = 
=
from (1)
= ar(CAD)
=
.
Hence, area of Δ ABD =
..
There is no way that he can run 151515km/h, but if he really can, then :
1 hour = 60 minutes
(151515km/h)/60minutes = 2525,25km/minute