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Ksju [112]
3 years ago
13

I need to find 5.29 divided by 6 Then 3.59 devided by 6 The. 4.79 divided by 6 thx

Mathematics
1 answer:
Naddika [18.5K]3 years ago
7 0
5.29/6 is 0.8816666666666666666666
3.59/6 is 0.5983333333333333333333
4.79/6 is 0.7983333333333333333333
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What is the sum of these expressions: (-3.5t - 4s + 4.5) + (-7.1 - 0.3s + 4.1t)
dmitriy555 [2]
-4.3s + 0.6t - 2.6 is the answer
4 0
3 years ago
find the area of triangle qpm. round the answer to the nearest tenth. a. 5.2 square units b. 6.3 square units c. 6.5 square unit
viva [34]
Pls. see attachment. 

We need to solve for the angles of the smaller triangle in order to solve for the angle of the larger triangle which would help us solve the missing measurement of a side.

Given:

51 degrees.

Cut the triangle into two equal sides and it forms a right triangle. All interior angles of a triangle sums up to 180 degrees.

180 – 51 – 90 = 39 degrees

39 degrees * 2 = 78 degrees.

Angle Q is 78 degrees.

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Sin(78 deg) = opposite / 4.3

Sin(78 deg) * 4.3 = opposite

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7 0
3 years ago
Use the grouping method to factor the polynomial below completely 3x^3+9x^2+5x+15​
Tomtit [17]

Answer:

(x+3)( 3x^2 +5)

Step-by-step explanation:

3x^3+9x^2+5x+15​

Split into two groups

3x^3+9x^2     +5x+15​

Factor 3x^2 out of the  first group and 5 out of the second group

3x^2 ( x+3)  + 5(x+3)

Factor out x+3

(x+3)( 3x^2 +5)

6 0
3 years ago
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skad [1K]

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with 0 ≤ u ≤ π/2 and 0 ≤ v ≤ π/2.

Compute the outward-pointing normal vector to S :

\vec n = \dfrac{\partial\vec s}{\partial v} \times \dfrac{\partial \vec s}{\partial u} = \left\langle 16 \cos(u) \sin^2(v), 16 \sin(u) \sin^2(v), 16 \cos(v) \sin(v) \right\rangle

The integral of the field over S is then

\displaystyle \iint_S \vec f \cdot d\vec s = \int_0^{\frac\pi2} \int_0^{\frac\pi2} \vec f(\vec s) \cdot \vec n \, du \, dv

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2 years ago
The blue are the two boards that you need to use.
ad-work [718]

Answer:

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Step-by-step explanation:

7 0
3 years ago
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