Multiples of 30 : 30,60,90,120,150....
and the first one that 4 goes into evenly is 60
We are asked to express the diagonal of a rectangle in terms of the width in which the area of the polygon is equal to 13 square feet. The area of teh rectangle is equal to length times width. That is 13 = lw; diagonal using pythagorean theorem is sqrt ( l2 + w2). Thus d = sqrt ( (13/w)2 + w2) = sqrt ( (169/w2 + w2) = sqrt ( (169 + w4)/w2) = 1/w sqrt (169 + w4)
Answer:
a. a = 1, b = -5, c = -14
b. a = 1, b = -6, c = 9
c. a = -1, b = -1, c = -3
d. a = 1, b = 0, c = -1
e. a = 1, b = 0, c = -3
Step-by-step explanation:
a. x-ints at 7 and -2
this means that our quadratic equation must factor to:

FOIL:

Simplify:

a = 1, b = -5, c = -14
b. one x-int at 3
this means that the equation will factor to:

FOIL:

Simplify:

a = 1, b = -6, c = 9
c. no x-int and negative y must be less than 0
This means that our vertex must be below the x-axis and our parabola must point down
There are many equations for this, but one could be:

a = -1, b = -1, c = -3
d. one positive x-int, one negative x-int
We can use any x-intercepts, so let's just use -1 and 1
The equation will factor to:

This is a perfect square
FOIL:

a = 1, b = 0, c = -1
e. x-int at 
our equation will factor to:

This is also a perfect square
FOIL and you will get:

a = 1, b = 0, c = -3
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