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3 years ago

How many terms are in the expression 3x^6yz+x^4y^2+2xz^5-6x^2y^3-7y

Mathematics

2 answers:

olasank [31]3 years ago

4 0

Answer:

Step-by-step explanation:

The terms in an equation are separated by a plus or minus sign, so here, there are five terms:

3x^6yz

z^4y^2

2xz^5

6x^2y^3

uysha [10]3 years ago

4 0

Answer:

The correct answer is 5

Step-by-step explanation:

The given expression is given by,

3x^6yz + x^4y^2 + 2xz^5 - 6x^2y^3 - 7y

<u>To find the number of terms</u>

We have to split each terms,

1). 3x^6yz

2). x^4y^2

3). 2xz^5

4). 6x^2y^3

5). 7y

From above we get there are five terms in the given expression 3x^6yz + x^4y^2 + 2xz^5 - 6x^2y^3 - 7y.

Therefore the correct answer is 5

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Answer:

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Step-by-step explanation:

Margin of error = critical value × standard error

At 90% confidence, the critical value is 1.645.

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0.05 = 1.645 √(0.52 (1 − 0.52) / n)

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3 0

3 years ago

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3 years ago

Use properties of limits and algebraic methods to find the limit, if it exists. (If the limit is infinite, enter '[infinity]' or

soldi70 [24.7K]

Answer:

The limit of this function does not exist.

Step-by-step explanation:

$\lim_{x \to 3} f(x)$

$f(x)=\left \{ {{9-3x} \quad if \>{x \>< \>3} \atop {x^{2}-x }\quad if \>{x\ \geq \>3 }} \right.$

To find the limit of this function you always need to evaluate the one-sided limits. In mathematical language the limit exists if

$\lim_{x \to a^{-}} f(x) = \lim_{x \to a^{+}} f(x) =L$

and the limit does not exist if

$\lim_{x \to a^{-}} f(x) \neq \lim_{x \to a^{+}} f(x)$

Evaluate the one-sided limits.

The left-hand limit

$\lim_{x \to 3^{-} } 9-3x= \lim_{x \to 3^{-} } 9-3*3=0$

The right-hand limit

$\lim_{x \to 3^{+} } x^{2} -x= \lim_{x \to 3^{+} } 3^{2}-3 =6$

Because the limits are not the same the limit does not exist.

8 0

3 years ago

Pleasee help me, I don’t get it

Aleks [24]

Answer:

x = 4 sqrt(5)

Step-by-step explanation:

Since this is a right triangle, we can use the Pythagorean theorem

a^2 + b^2 = c^2 where a and b are the legs and c is the hypotenuse

8^2 + x^2 = 12^2

64+ x^2 =144

Subtract 64 from each side

x^2 = 144-64

x^2 =80

Take the square root of each side

sqrt(x^2) = sqrt(80)

x = sqrt(16*5)

x = 4 sqrt(5)

8 0

3 years ago

Mark would like to build a rectangle frame. The dimensions of the frame are unknown, but the perimeter of the frame must be 80 y

kotykmax [81]

Answer:

The length of the frame is 17

Step-by-step explanation:

The computation of the length of the frame is shown below:

As we know that

The perimeter of a rectangle is

= 2 (length + width)

where,

let us assume the width be x

So, the length is x - 6

And, the perimeter is 80 yards

So, now put these values to the above formula

80 yards = 2 (x - 6+ x)

80 yards = 2 (2x - 6)

80 yards = 4x - 12

92 = 4x

x = 23

So, the length of the frame is

= 23 - 6

= 17

6 0

3 years ago