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goldenfox [79]
3 years ago
13

Break this problem down 22-[(87-32)÷5]×2

Mathematics
1 answer:
pochemuha3 years ago
6 0
22-[(87-32)/5]x2
22-[(55)/5]x2
22-11x2
22-22
0
Answer is 0
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Can someone help me please
Darya [45]

Answer:

a^7/b^6

Step-by-step explanation:

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3 years ago
Tara has 2000 in her savings account David has 1/10 as much as Tara in his account how much does David have in his savings accou
Paraphin [41]
200$ because if you do 2000dovided by 10 then it will equal=200 so loook 200x10=2000 so 1/10=200
7 0
3 years ago
What is equation of a line that is parallel to y = -6x – 1 and passes through the point (1,4)
Akimi4 [234]

Answer:

y = -6x + 10

Step-by-step explanation:

Parallel lines share the same slope.  Given y = -6x – 1, we know that the equation of this new line has the form y = -6x – C.  The coordinates of the point (1, 4) determine the value of C:

(4) = -6(1) – C, or:

4 = -6 - C

Then C = -10, and the desired equation is

y = -6x – (-10), or

y = -6x + 10

5 0
3 years ago
In the month of June, the temperature in Johannesburg, South Africa, varies over the day in a periodic way that can be modeled a
Art [367]

Answer:

The answer is "\bold{T = - 7.5 \cos \frac{\pi}{12}( t - 4 )+ 10.5}"

Step-by-step explanation:

Given value:

Temp-maximum=18^{\circ}  

Temp. minimum = 3^{\circ}

It is halfway between 10 am and 10 pm to 4 am.  

The sinus and cosine roles could be used throughout the year to predict fluctuations in climate models. Its type of formula that can be used to model such information is:  

T = A \cos B(t-C) + D, where parameters are A, B , C, D, T is the ° C temperature and t is the time (1-24)

A = amplitude = \frac{(T_{max} - T_{min})}{2}\\\\

                       = \frac{(3 - 18)}{2}\\\\= - \frac{15}{2}\\\\ = -7.5

B = \frac{2 \pi}{24}\\\\

   = \frac{\pi}{12}

C = \text{ units translated to the right}= 4

D = y_{min} + amplitude = units \ translated \ up\\\\

D = 7.5 + 3 = 10.5

Its trigonometric function equation that model temperature T hours after midnight in Johannesburg t.

T = - 7.5 \cos \frac{\pi}{12}( t - 4 )+ 10.5

6 0
4 years ago
CAN SOMEONE GOOD AT MATH HELP PLEEESE!!
Rufina [12.5K]

Answer: 1 .Thus for a graph to have an Euler circuit, all vertices must have even degree. The converse is also true: if all the vertices of a graph have even degree, then the graph has an Euler circuit, and if there are exactly two vertices with odd degree, the graph has an Euler path.

2. A graph has an Euler circuit if and only if the degree of every vertex is even. A graph has an Euler path if and only if there are at most two vertices with odd degree.

Step-by-step explanation:

Can i have branily plz

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