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grigory [225]
3 years ago
15

Find the quotient. 54÷1112 =

Mathematics
1 answer:
Dvinal [7]3 years ago
6 0

Answer: 0.0485610791367

Step-by-step explanation:

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94 1/4 divided by 7 1/4
Lerok [7]
The answer is 13 :)))
6 0
3 years ago
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A certain substance in an experiment was being stored at −2.4°F. It was then placed on a table where the temperature was raised
Fynjy0 [20]

Answer:

2.9 F

Step-by-step explanation:

5 0
3 years ago
Factor completely:<br>64 - y^3
madam [21]
From your equation, you can see that you have a difference of two cubes (aka two cubes being subtracted): 64, which is 4^{3}, and y^{3}.

There is rule for the difference of two cubes:
The difference of two cubes is equal to the difference of the cube roots times a binomial, which is the sum of the squares of the roots plus the product of the roots.

That sounds pretty confusing, but it's much easier to understand when put mathematically. Let's say our two cubes are a^{3} and b^{3}. The difference of those two cubes is:
a^{3} - b^{3} = (a - b)( a^{2} + ab + b^{2})

In our problem, a = 4 (since a^{3} = 64) and b = y (since b^{3} = y^{3}. Plug these values into the rule to find the factor of 64 - y^3:
64 - y^3 \\&#10;= (4 - y)( 4^{2} + 4y + y^{2}) \\&#10;=  (4 - y)( 16 + 4y + y^{2})

-----

Answer: (4 - y)( 16 + 4y + y^{2})

8 0
3 years ago
Find the area of the missing piece of the polygon and explain your process for finding it:
Otrada [13]

Answer:

42

Step-by-step explanation:

In short, the sum of the opposite areas are equal.

x + 30 = 24 + 48

x = 42

To prove this, draw a line from each corner to the "center" where the four lines meet.  Along each side of the square are two triangles.  These triangles have the same base and the same height, and therefore have the same area.

If we say the triangles at the bottom have area a, the triangles on the left have area b, the triangles on top have area c, and the triangles on the right have area d, then we can write 4 equations:

a + b = x

b + c = 24

c + d = 30

a + d = 48

Adding the first and third equations:

a + b + c + d = x + 30

Adding the second and fourth equations:

a + b + c + d = 24 + 48

Therefore:

x + 30 = 24 + 48

x = 42

8 0
3 years ago
A cell phone provider classifies its customers as Low users (less than 400 minutesper month) or High users (400 or more minutes
Svet_ta [14]

Answer:

a ) See step by step explanation

b) 50%   and  50%

Step-by-step explanation:

The definition of type of user x is:

if x < 400 minutes  per month  low user

if x > 400 minutes per month  high user

The value for these states are of course yes  or no  ( the user is low or high user)

Then:

if the user is low today  xt  (0)    we have the probability of 80% ( 0,8) of have the user in the same condition and 20% (0,2) of having him or her as high user

xt = 1      

If the user is high today xt (1) is high today we have the probability of 70% ( 0,7) of having  the user in the same condition and 30% (0,3) of having him or her as high user

a) Then we construct the stochastic matrix

 Type of user

         (xt)               xt         xt+1  

      Low (0) or L   0,8        0,2

     High(1)  or H   0,3        0,7

The resulting equation system is:

xt  =  0,8* xt  +  0,2* xt+1

xt+1  = 0,3*xt + 0,7* xt+1

1  =  xt + xt+1

Solving for variables         xt+1  =  1  - xt

xt  = 0,8*xt + ( 1 - xt ) * 0,2

xt - 0,8*xt = 0,2 - 0,2xt

xt - 0,6*xt = 0,2

0,4*xt = 0,2

xt = 0,5       and     xt+1  = 0,5

b)  If in January 0,5  ( 50%) of customesr were  low user

In february  teh % of low user customer wll be

xt  =  0,8* xt  +  0,2* xt+1

0,5 = 0,8*0,5 + 0,2*xt+1

0,5 = 0,4 + 0,2 *xt+1

0,1/0,2 = xt+1        xt+1 = 0,5       or   50%

The same answer for March

7 0
3 years ago
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