A)
i) C(n)=42n
ii)C(n,x)=15n+0.25x
b)She plans to drive a total of 600 Km, therefore: x=600
Budget: C(n)=42n
Deluxe: C(n,x)=15n +0.25(600)=15n+150
Cost of Budget< Cost of Deluxe
42n<15n+150
42n-15n<150
27n<150
n<150/27
n<5.5 ⇒n<5
Answer: The maximum number of days would be 5 days.
0.272727273. Hope this helps.
Equation of the table is given by
y - 210 = (280 - 210)/(4 - 3) (x - 3)
y - 210 = 70(x - 3)
y - 210 = 70x - 210
y = 70x
When x = 11, y = 70(11) = 770
Equation of the graph is given by
y = 110/2 x = 55x
When x = 11, y = 55(11) = 605
Therefore the value of y in the table is grater than the value of y in the graph by 770 - 605 = 165
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