30x + 20y +55 ANSWER ASAP

I WILL MARK YOU AS BRANLIEST JUST DO THIS PLS ASAP

tensa zangetsu [6.8K]

Answer:

(6t) + (3t) + (4t)

Simplified it would be 13t

3 0

3 years ago

What is the range of f(x)= -3^x+4

V125BC [204]

Answer:

A. The set of all real numbers less than 4

Step-by-step explanation:

The range of the parent function $y=3^x$ is $y\in (0,\infty)$

The graph of the function $y=-3^x$ is reflected across the x-axis graph of the parent function, so the range of the function $y=-3^x$ is $(-\infty,0)$

The graph of the function $y=-3^x+4$ is translated 4 units up graph of the function $y=-3^x$ , so the range of the function $y=-3^x+4$ is $(-\infty,4)$ or the set of all real numbers less than 4.

7 0

4 years ago

1+secA/sec A = sin^2 A / 1-cos A

Fofino [41]

Answer: see proof below

Step-by-step explanation:

$\dfrac{1+\sec A}{\sec A}=\dfrac{\sin^2 A}{1-\cos A}$

Use the following Identities:

sec Ф = 1/cos Ф

cos² Ф + sin² Ф = 1

Proof LHS → RHS

$\text{LHS:}\qquad \qquad \dfrac{1+\sec A}{\sec A}$

$\text{Identity:}\qquad \qquad \dfrac{1+\frac{1}{\cos A}}{\frac{1}{\cos A}}$

$\text{Simplify:}\qquad \qquad \dfrac{\frac{\cos A+1}{\cos A}}{\frac{1}{\cos A}}\\\\\\.\qquad \qquad \qquad =\dfrac{1+\cos A}{1}$

$\text{Multiply:}\qquad \qquad \dfrac{1+\cos A}{1}\cdot \bigg(\dfrac{1-\cos A}{1-\cos A}\bigg)\\\\\\.\qquad \qquad \qquad =\dfrac{1-\cos^2 A}{1-\cos A}$

$\text{Identity:}\qquad \qquad \dfrac{\sin^2 A}{1-\cos A}$

$\text{LHS = RHS:}\quad \dfrac{\sin^2 A}{1-\cos A}=\dfrac{\sin^2 A}{1-\cos A}\quad \checkmark$

3 0

4 years ago

A dance class consists of 22 students, of which 10 are women and 12 are men. if 5 men and 5 women are to be chosen and then pair

OverLord2011 [107]

solution:

I choose 5 women from a pool of 10 in 10C2 ways.

I choose 5 men from a pool of 12 in 12C2 ways.

So total number of ways of choosing in 10C2 x 12C2. Now I need to arrange them in 5 pairs. This is where I have a different solution. The solution says that there are 5! ways to arrange them in pairs.

But I cant seem to understand why? My reasoning is that for first pair position I need to choose 1 man from 5 and 1 woman from 5. So for the first position I have 5 x 5 choices (5 for man and 5 for woman). Similarly for the second position I have 4 x 4 choices and so on. Hence the total ways are 5! x 5!

So I calculate the total ways as 10C2 * 12C2 * 5! * 5!. Can anyone point the flaw in my reasoning for arranging the chosen men and women in pairs.

3 0

4 years ago

When adding two rational numbers what will the sign be if both numbers are positive?

NikAS [45]

Answer:

Step-by-step explanation:

Adding two rational numbers results in a positive sum.

4 0

3 years ago