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Reika [66]
3 years ago
10

30x + 20y +55 ANSWER ASAP

Mathematics
1 answer:
vazorg [7]3 years ago
7 0

Answer:

are there any options?

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Elvira used 4 cups of grape juice, 1 1/2 cups of cranberry juice, and 1/2 cup of pineapple juice to make punch. One liter
Mandarinka [93]
4+1.5+.5= 6 cups

6 cups = 1.42 liters

Closest measurement is 1.42L
3 0
3 years ago
HELPPPP 100 points if you help!!!!
nignag [31]

Answer:

Part A)

Chorus:

c(t)=15(1.12)^t

Band:

b(t)=2t+30

Part B)

After 9 years:

The chorus will have about 41 people.

And the band will have 48 people.

Part C)

About approximately 11 years.

Step-by-step explanation:

We are given that there are 15 people in the chorus. Each year, number of people in the chorus increases by 12%. So, the chorus increases exponentially.

There are 30 people in the band. Each year, 2 new people join the band. So, the band increases linearly.

Part A)

Since after each year, the number of people in the chorus increases by 12%, the new population will be 112% or 1.12 of the previous population.

So, using the standard form for exponential growth:

c(t)=a(r)^t

Where <em>a</em> is the initial population and <em>r</em> is the rate of change.

We will substitute 15 for <em>a </em>and 1.12 for <em>r</em>. Hence:

c(t)=15(1.12)^t

This represents the number of people in the chorus after <em>t</em> years.

We are given that 2 new people join the band each year. So, it increases linearly.

Since there are already 30 people in the band, our initial point or y-intercept is 30.

And since 2 new people join every year, our slope is 2. Then by the slope-intercept form:

b(t)=mt+b

And by substitution:

b(t)=2t+30

This represents the number of people in the band after <em>t</em> years.

Part B)

We want to find the number of people in the chorus and the band after 9 years.

Using the chorus function, we see that:

c(9)=15(1.12)^9\approx41.59\approx41

There will be approximately 41 people in the chorus after 9 years.

And using the band function, we see that:

b(9)=2(9)+30=48

There will be 48 people in the band after 9 years.

Part C)

We want to determine after approximately how many years will the number of people in the chorus and band be equivalent. Hence, we will set the two functions equal to each other and solve for <em>t</em>. So:

15(1.12)^t=2t+30

Unfortunately, it is impossible to solve for <em>t</em> using normal analytic methods. Hence, we can graph them. Recall that graphically, our equation is the same as saying at what point will our two functions intersect.

Referring to the graph below, we can see that the point of intersection is at approximately (10.95, 51.91).

Hence, after approximately 11 years, both the chorus and the band will have approximately 52 people.

5 0
3 years ago
You have $8 and earn $1.25 for each health bar you sell. Write an equation in two variables that represent the total amount A (i
kherson [118]
The equation is
A= 8 + (1.25*b)
7 0
2 years ago
What is the equation of the line that goes through the points (4,6) and (2,12)?
KengaRu [80]

Answer:

6.72

Step-by-step explanation:

6 0
2 years ago
Find the midpoint of PQ<br><br> P(4 1/3, 3 1/6), Q(-2 1/5, 3 2/3)
Paha777 [63]

Answer:

(1\frac{1}{15},3\frac{5}{12})

Step-by-step explanation:

To find the midpoint, you must average the x's then average the y's.

So the x's are 4 \frac{1}{3} and -2\frac{1}{5}.

The y's are 3\frac{1}{6} and 3\frac{2}{3}.

To find an average of a data with 2 elements you must add the two elements then take that sum and divide it by 2.

So this is what we will do with the x's then the y's.

So first x:

\frac{4\frac{1}{3}+-2\frac{1}{5}}{2}

Write as improper fractions:

\frac{\frac{13}{3}+\frac{-11}{5}}{2}

Division by 2 is the same as multiplying by 1/2:

\frac{13}{6}+\frac{-11}{10}

The least common multiple of 6 and 10 is 30.  We will multiply first fraction by 5/5 and 3/3 for the second so we can have the same denominator.

\frac{65}{30}+\frac{-33}{30}

Now that the bottoms are the same we can write as one fraction:

\frac{65+-33}{30}

Simplify:

\frac{32}{30}

If you want the answer as a mix fraction like your question began as we can do that by first figuring out how many 30's are in 32 and what is the remainder of that division.

There is one 30 and 32 and so 32-30=2 is the remainder.

1\frac{2}{30}

Reduce by dividing top and bottom by 2:

1\frac{1}{15}

Now for y:

\frac{3\frac{1}{6}+3\frac{2}{3}}{2}

Write the mix fractions as improper fractions:

\frac{\frac{19}{6}+\frac{11}{3}}{2}

Dividing by 2 is the same as multiplying by 1/2:

\frac{19}{12}+\frac{11}{6}

The least common multiple of 12 and 6 is 12 so I'm going to multiply the second fraction by 2/2 so the denominators will be the same:

\frac{19}{12}+\frac{22}{12}

Since the denominators are the same we can write as a single fraction:

\frac{41}{12}

How many 12's are in 41? 3 and so the remainder is 41-3(12)=41-36=5.

3\frac{5}{12}

So the midpoint is:

(1\frac{1}{15},3\frac{5}{12}).

6 0
3 years ago
Read 2 more answers
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