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2 years ago

Find an equation of the straight line that is perpendicular to the straight line x+2y=5 and that passes through the point (3,7)

Mathematics

1 answer:

Digiron [165]2 years ago

7 0

Answer: y = 2x + 1

Step-by-step explanation:

Rewrite the equation in standard form:

x+2y=5

2y = -x + 5

y = -(1/2)x + (5/2)

A line perpendicular to this would have a slope that is the negative inverse of the reference line slope, -(1/2), here. The new slope would be 2. The y-intercept, (5/2), will change, so we'll just use b for the new y-intercept, and calculate it later:

y = 2x +b

We know that point (3,7) lies on the new line (it is a solution to the equation), so we can use this point to find the new y-intercept, b.

7 = 2*3 + b

b = 1

The perpendicular line is y = 2x + 1, and goes through point (3,7)

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crimeas [40]

Answer:

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3 years ago

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Question 1.) 267.935:39=

Answer 1.) 6.870 approximately

Question 2.) 689.354:78

Answer 2.) 8.838 approximately

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Answer 3.) 1.730 approximately

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3 years ago

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VikaD [51]

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3 years ago

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Answer:

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prohojiy [21]

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