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1 year ago

Find an equation of the straight line that is perpendicular to the straight line x+2y=5 and that passes through the point (3,7)

Mathematics

1 answer:

Digiron [165]1 year ago

7 0

Answer: y = 2x + 1

Step-by-step explanation:

Rewrite the equation in standard form:

x+2y=5

2y = -x + 5

y = -(1/2)x + (5/2)

A line perpendicular to this would have a slope that is the negative inverse of the reference line slope, -(1/2), here. The new slope would be 2. The y-intercept, (5/2), will change, so we'll just use b for the new y-intercept, and calculate it later:

y = 2x +b

We know that point (3,7) lies on the new line (it is a solution to the equation), so we can use this point to find the new y-intercept, b.

7 = 2*3 + b

b = 1

The perpendicular line is y = 2x + 1, and goes through point (3,7)

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