Answer:
40 m
Step-by-step explanation:
The perimeter of the flat, orange shape is the sum of all the sides that forms a boundary around the shape.
The shape is made up of 4 triangles having 2 equal side lengths each, which surrounds the center square.
Each side length of the triangle, that forms a boundary round the shape = 5 m.
There are 8 of this equal side length.
Perimeter = 8(5m) = 40 m
The slope is 1/4 and the y-intercept is 2
Answer:
(-2, 20)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
<u>Algebra I</u>
- Coordinates (x, y)
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
y = -7x + 6
y = -10x
<u>Step 2: Solve for </u><em><u>x</u></em>
<em>Substitution</em>
- Substitute in <em>y</em> [1st Equation]: -10x = -7x + 6
- [Addition Property of Equality] Add 7x on both sides: -3x = 6
- [Division Property of Equality] Divide -3 on both sides: x = -2
<u>Step 3: Solve for </u><em><u>y</u></em>
- Substitute in <em>x </em>[2nd Equation]: y = -10(-2)
- Multiply: y = 20
Answer:
f(x) = -(x-3)^2 + 4
Step-by-step explanation:
(h; k) are the coordinates of the vertex.
On the graph are (3, 4), therefore we have:
f(x) = a(x-3)^2 + 4
We have the x- intercept (1,0) -> x=1; y=0.
Substitute them into the equation:
0 = a(1 - 3)^2 + 4
0 = a(-2)^2 + 4
4a + 4 = 0 | -4
4a = -4 |-4
a = -1
So, we have the answer:
f(x) = -(x-3)^2 + 4
Answer:
Inequalities are,
y ≥ 4x + 2
y ≥ 2
Step-by-step explanation:
Solid yellow line of the graph attached passes through two points (0, -2) and (1, 2).
Let the equation of this line is,
y = mx + b
Slope of the line = 
m = 
m = 4
Y-intercept 'b' = -2
Equation of the line will be,
y = 4x - 2
Since shaded area is on the left side of this solid line so the inequality representing this region will be,
y ≥ 4x - 2
Another line is a solid blue line parallel to the x-axis.
Shaded region (blue) above the line will be represented by,
y ≥ 2
Therefore, the common shaded area of these inequalities will be the solution of the given inequalities.
