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3 years ago

Jerrold ran a race that was 3 5/8 miles long. What is 3 5/8 written as a decimal?

Mathematics

1 answer:

Feliz [49]3 years ago

8 0

Answer:

3.625

step by step explanation :

I just simply searched it up

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Calculate the volume of a cylinder of diameter 6cm and height 10cm

masya89 [10]

Answer:

565.2

Step-by-step explanation:

565.2

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3 years ago

Does anyone know how to do this?

Vlad1618 [11]

Answer:i think you have to equal them to each other

Step-by-step explanation:

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3 years ago

For many years businesses have struggled with the rising cost of health care. But recently, the increases have slowed due to les

kaheart [24]

Answer:

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

The margin of error for this case is given by:

$ME= z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

And replacing we got:

$ME = 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.0259$

And replacing into the confidence interval formula we got:

$0.52 - 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.4941$

$0.52 + 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.5459$

And the 95% confidence interval would be given (0.4941;0.5459).

Step-by-step explanation:

Data given and notation

n=1000 represent the random sample taken

$\hat p=0.52$ estimated proportion of of U.S. employers were likely to require higher employee contributions for health care coverage

$\alpha=0.05$ represent the significance level (no given, but is assumed)

Solution to the problem

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

The margin of error for this case is given by:

$ME= z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

And replacing we got:

$ME = 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.0259$

And replacing into the confidence interval formula we got:

$0.52 - 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.4941$

$0.52 + 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.5459$

And the 95% confidence interval would be given (0.4941;0.5459).

5 0

2 years ago

What is 3/12 equivalent to ?/100

enyata [817]

Answer:

25/100

Step-by-step explanation:

3/12 can be simplified to 1/4

3 0

2 years ago

Find the arc length of the partial circle.

Maru [420]

Answer:

$11$

Step-by-step explanation:

$\frac{90}{360} \times 2 \times \pi \times 7 \\ \frac{1}{4} \times 2 \times \frac{22}{7} \times 7 \\ = 11$

4 0

3 years ago

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