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3 years ago

13

Can you please help me

2 answers:

Goshia [24]3 years ago

8 0

Answer:

You start with 4 pounds of oranges, and every other pound is a <em>k</em> varaible, which is added to the totall amount of pounds at checkout

Step-by-step explanation:

By verbal I hope you meant word problem?

cestrela7 [59]3 years ago

5 0

Answer:

The sum of 4 and an integer.

Step-by-step explanation:

To solve this problem we need to transform the expression written in an algebraic form to a verbal statement.

In this expression, first of all we can notice that the operation given is a sum.

One of the numbers is 4 and the other number is represented by the letter k. Since we are not given any conditions on the k, we could say that k is any number (although in math, the k usually represents an integer, so we'll consider k to be an integer).

Thus, 4 + k would be expressed as "the sum of 4 and an integer"

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Need help with this maybe question

Aleonysh [2.5K]

Answer:

the vertex is:

(2, -1)

Step-by-step explanation:

First solve the equation for the variable y

$x^2-16y-4x-12=0$

Add 16y on both sides of the equation

$16y=x^2-16y+16y-4x-12$

$16y=x^2-4x-12$

Notice that now the equation has the general form of a parabola

$ax^2 +bx +c$

In this case

$a=1\\b=-4\\c=-12$

Add $(\frac{b}{2}) ^ 2$ and subtract $(\frac{b}{2}) ^ 2$ on the right side of the equation

$(\frac{b}{2}) ^ 2=(\frac{-4}{2}) ^ 2$

$(\frac{b}{2}) ^ 2=(-2) ^ 2$

$(\frac{b}{2}) ^ 2=4$

$16y=(x^2-4x+4)-4-12$

Factor the expression that is inside the parentheses

$16y=(x-2)^2-16$

Divide both sides of the equality between 16

$\frac{16}{16}y=\frac{1}{16}(x-2)^2-\frac{16}{16}$

$y=\frac{1}{16}(x-2)^2-1$

For an equation of the form

$y=a(x-h)^2 +k$

the vertex is: (h, k)

In this case

$h=2\\k =-1$

the vertex is:

(2, -1)

6 0

3 years ago

I need help. please answer.

lana66690 [7]

Answer:

B

Step-by-step explanation:

7 0

3 years ago

Help please I will mark Brainly <br> If you could please show your work

kondaur [170]

Answer:

tawag sa manok na pansabong

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