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2 years ago

Can you please help me

Mathematics

2 answers:

Goshia [24]2 years ago

8 0

Answer:

You start with 4 pounds of oranges, and every other pound is a k varaible, which is added to the totall amount of pounds at checkout

Step-by-step explanation:

By verbal I hope you meant word problem?

cestrela7 [59]2 years ago

5 0

Answer:

The sum of 4 and an integer.

Step-by-step explanation:

To solve this problem we need to transform the expression written in an algebraic form to a verbal statement.

In this expression, first of all we can notice that the operation given is a sum.

One of the numbers is 4 and the other number is represented by the letter k. Since we are not given any conditions on the k, we could say that k is any number (although in math, the k usually represents an integer, so we'll consider k to be an integer).

Thus, 4 + k would be expressed as "the sum of 4 and an integer"

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1. If one painter can paint a house in 4 days and another painter can paint a house in 7 days, how many days will it take them w

enyata [817]

9514 1404 393

Answer:

2 6/11 days
1 2/3 hours

Step-by-step explanation:

1. Add the rates in terms of houses per day.

1/4 + 1/7 = (7+4)/28 = 11/28

Then the time required in terms of days per house is the reciprocal of this:

28/11 = 2 6/11 . . . . days to paint a house, working together

2. Each hour, the vehicles separate by 55 -40 = 15 miles. Then the time required for a separation of 25 miles is ...

time = distance/speed = (25 mi)/(15 mi/h_ = 5/3 h = 1 2/3 h

The vehicles will be separated by 25 miles after 1 2/3 hours.

6 0

3 years ago

Given: △ABC, m∠A=60°

Anon25 [30]

Answer:

Perimeter = 32.3

Area = 95.24

Step-by-step explanation:

Given:

△ABC, m∠A=60°

m∠C=45°, AB = 9

To find:

Perimeter of △ABC

Area of △ABC

Solution:

Using angle sum property in a triangle:

m∠A + m∠B + m∠C = 180°

m∠B = 180° - 45° - 60° = 75°

As per Sine Rule:

$\dfrac{a}{sinA} = \dfrac{b}{sinB} = \dfrac{c}{sinC}$

Where

$a$ is the side opposite to $\angle A$

$b$ is the side opposite to $\angle B$

$c$ is the side opposite to $\angle C$

$\dfrac{BC}{sin60^\circ} = \dfrac{AC}{sin 75^\circ} = \dfrac{AB}{sin 45^\circ} \\\Rightarrow \dfrac{BC}{\frac{\sqrt3}{2}} = \dfrac{9}{\frac{1}{\sqrt2}} \\\Rightarrow BC = 12.73\times 0.87 \\\Rightarrow BC = 11.08$