HELP I WILL GIVE ALl MY POINTS NEXT QUESTION TO TH PERSON WHO ANSWERS RIGHT HELPP

A television network is about to telecast a new television show. Before a show is launched, the network airs a pilot episode and

GalinKa [24]

Let's first denote:

F - a favorable response

F' - an unfavorable response

S - successful

We know that:

$P(F) = 0.6\\\\P(F')=0.4\\\\P(F\cap S)=0.5\\\\P(F'\cap S)=0.3$

So, from the conditional probability, we can calculate:

$P(S|F) = \dfrac{P(S\cap F)}{P(F)} = \dfrac{0.5}{0.6}=\dfrac{5}{6}\approx\boxed{0.83}$

Answer E.

5 0

3 years ago

(1+cos2x)/(1-cos2x) = cot^2x

sesenic [268]

We will turn the left side into the right side.

$\dfrac{1 + \cos 2x}{1 - \cos2x} = \cot^2 x$

Use the identity:

$\cos 2x = \cos^2 x - \sin^2 x$

$\dfrac{1 + \cos^2 x - \sin^2 x}{1 - ( \cos^2 x - \sin^2 x)} = \cot^2 x$

$\dfrac{1 - \sin^2 x + \cos^2 x }{1 - \cos^2 x + \sin^2 x} = \cot^2 x$

Now use the identity

$\sin^2 x + \cos^2 x = 1$ solved for sin^2 x and for cos^2 x.

$\dfrac{\cos^2 x + \cos^2 x }{\sin^2 x + \sin^2 x} = \cot^2 x$

$\dfrac{2\cos^2 x}{2\sin^2 x} = \cot^2 x$

$\dfrac{\cos^2 x}{\sin^2 x} = \cot^2 x$

$\cot^2 x = \cot^2 x$

8 0

3 years ago

The two right scalene triangles shown are similar , but not congruent. Which statement about the triangles is not true

garri49 [273]

Answer: <CDB corresponds to <ECD

Step-by-step explanation:

The angles in similar triangles correspond to each other.

For two angles in similar triangles to correspond to each other, then they have to be in the same position in the triangle. (EX: a 90 degree angle corresponds to another 90 degree angle or an angle across from the shortest side corresponds to another angle in the other triangle across from the shortest side)

In this case, <CDB is to the right of the 90 degree angle, so the angle it will correspond to is the angle in the other triangle which is opposite to the 90 degree angle, which is <CED.

<CED is not <ECD, so that answer is wrong.

Tell me if I need to clarify anything - this topic is kind of hard to explain :/

3 0

3 years ago

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A little help, please? Greg is designing a clock face. Using the center of the clock face as the origin, he keeps its diameter a

gayaneshka [121]

I don’t know the answer but I hope someone else doesnt

3 0

3 years ago

On the attached drawing what is the name for Angle LHJ? Obtuse, acute, complementary or right?

Natasha2012 [34]

Answer: Right (Last option)

Step-by-step explanation:

As you can see in the figure, the parallel lines AD and GJ are intersected by two lines.

The line EL intersects the parallel lines and there are two angles that are formed by this intersections which are located on the exterior of AD and GJ, but on opposite sides of EL, (these angles are called "Alternate exterior angles" and they are congruent), which are:

∠LHJ and ∠EBA

You can observe that the angle ∠EBA is indicated with a square. This means that the measure of that angle is 90° (Right angle).

Therefore, if ∠EBA=90°, then ∠LHJ =90°

4 0

3 years ago

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