What is the distance between points A and B? A. 1/3B. 1/2C. 1 1/3D. 1 1/2

Mathematics

1 answer:

Savatey [412]3 years ago

4 0

Answer:

A. 1/3

Step-by-step explanation:

From 1 to ___, ____, and 2 is half and half that would be 2 and a half. the only solution would be 1/3

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Answer:

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Let the height of cake be H.

So, Height of third cake $=\sqrt{L^2+B^2+H^2}\\\\=\sqrt{5^2+6^2+H^2}\\\\=\sqrt{61+H^2}$

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In ΔABC, the lengths of a, b, and c are 22.5 centimeters, 18 centimeters, and 13.6 centimeters, respectively.

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Given the values of the three sides of the triangle, we can apply the Cosine Law to find the angles of the triangle. Recall that for we can express the value of c through the equation below.

$c^{2} = a^{2} + b^{2} - 2abcosC$

Rearranging this equation, we can find the value ∠C as shown below.

$\cos C = \frac{a^{2}+b^{2}-c^{2}}{2ab}$
$C = cos^{-1} (\frac{a^{2}+b^{2}-c^{2}}{2ab})$

We can apply the same reasoning for finding the value of ∠B as shown.

$B = cos^{-1} (\frac{a^{2}+c^{2}-b^{2}}{2ac})$

Plugging in the values of the sides (see image attached) from the given. It will now be straightforward to compute for ∠B and ∠C.

$C = cos^{-1} (\frac{22.5^{2}+18^{2}-13.6^{2}}{2(22.5)(18)})$
$C \approx 37.19$

$B = cos^{-1} (\frac{22.5^{2}+13.6^{2}-18^{2}}{2(22.5)(13.6)})$
$B \approx 53.13$

Answer: ∠C = 37.19° and ∠B = 53.13°