The solution would be like this for this specific problem:
H0: p = p0, or <span>
H0: p ≥ p0, or
H0: p ≤ p0 </span>
find the test statistic z
= (pHat - p0) / sqrt(p0 * (1-p0) / n)
where pHat = X / n
The p-value of the test is
the area under the normal curve that is in agreement with the alternate
hypothesis. <span>
H1: p ≠ p0; p-value is the area in the tails greater than |z|
H1: p < p0; p-value is the area to the left of z
H1: p > p0; p-value is the area to the right of z </span>
Hypothesis equation:
H0: p ≥ 0.67 vs. H1: p
< 0.67
The test statistic is: <span>
z = ( 0.5526316 - 0.67 ) / ( √ ( 0.67 * (1 - 0.67 ) / 38 )
z = -1.538681 </span>
The p-value = P( Z < z
) <span>
= P( Z < -1.538681 )
<span>= 0.0619</span></span>
Answer:
idek
Step-by-step explanation:
srry
Answer:
The answer is 3.785, but rounding it to the nearest hundredth is 3.68 or 3.79, depending on rather they wanted you to take the t and round up or just leave it off.
The missing justification in the proof is
<span>B) Substitution property of equality
The expression for sin</span>² x and cos² x is substituted to the other side of the equation. Since sin x = a/c, then sin² x = a²/c². Similarly, since cos x = b/c, then cos² x = b²/c². Adding to two results to the third statement.
