Answer:
One possible equation is 
, which is equivalent to 
.
Step-by-step explanation:
The factor theorem states that if 
(where 
is a constant) is a root of a function, 
would be a factor of that function.
The question states that 
and 
are 
-intercepts of this function. In other words, 
and 
would both set the value of this quadratic function to 
. Thus, 
and 
would be two roots of this function.
By the factor theorem, 
and 
would be two factors of this function.
Because the function in this question is quadratic, and would be the only two factors of this function. In other words, for some constant 
(
):
.
Simplify to obtain:
.
Expand this expression to obtain:
.
(Quadratic functions are polynomials of degree two. If this function has any factor other than and , expanding the expression would give a polynomial of degree at least three- not quadratic.)
Every non-zero value of corresponds to a distinct quadratic function with -intercepts and . For example, with 
:
, or equivalently,
.
Answer:non statistical
Step-by-step explanation:
Answer:
the answer is a where x=8
Explanation:
cross multiplication method
rewrite the equation set = to 0.
x^2 + 5x - 8 = 0
The quadratic will not factor so you have to use the quadratic formula.
x = (-b + - sqrt(b^2 - 4ac))/2a
x = (5 + - sqrt(25 - 4* 1* -8))/2
x = (5 + - sqrt 57)/2
The x2is not the same as 2x. It is x^2. X tot he second power which makes the problem a quadratic equation. You cannot combine the terms x^2 and -5x because they so not have the same power.
