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STALIN [3.7K]
2 years ago
5

Plss help ill give brainlest

Mathematics
1 answer:
Ede4ka [16]2 years ago
5 0
The length of the truck could explain how many wheels trucks have
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Indicate the equation of the given line in standard form. The line through the midpoint of and perpendicular to the segment join
lianna [129]
The midpoint is (3,-1) 

5 0
3 years ago
Help asap thank you .
frosja888 [35]

Answer:

2

Step-by-step explanation:

count up 2 count right 1, 2/1

2/1 = 2

3 0
2 years ago
Help plzzzzzzzzz????? asapp
Fiesta28 [93]
The two angles are a linear pair.
(Explanations down below!)

Linear pair angles must add up to 180 degrees. You can tell that the two angles add up to 180 degrees because they form a straight line (which is 180 degrees).

Complementary angles add up to 90 degrees. The two angles are not complementary because they do not form a 90 degree angle (right triangle, square in corner, like a L shape).

Vertical angles are opposite each other and are equal to one another. These angles are adjacent to each other and do not look similar.
6 0
3 years ago
What is and equation line that passes through the point (8,-5) and is parallel to the line 5x+4y=24
GenaCL600 [577]

Answer:

5x + 4x = 20

Step-by-step explanation:

You have your x and y values and if you substitute them in you find yourself with 40 - 20 = 24 this doesn't make sense. So you get another answer which can be set to 20 and 40 - 20 = 20 therefore you you can make sure that your line intersects with your x and y values.

4 0
3 years ago
The manufacturer of a CD player has found that the revenue R​ (in dollars) is Upper R (p )equals negative 5 p squared plus 1 com
AleksAgata [21]

Answer:

The maximum revenue is $1,20,125 that occurs when the unit price is $155.

Step-by-step explanation:

The revenue function is given as:

R(p) = -5p^2 + 1550p

where p is unit price in dollars.

First, we differentiate R(p) with respect to p, to get,

\dfrac{d(R(p))}{dp} = \dfrac{d(-5p^2 + 1550p)}{dp} = -10p + 1550

Equating the first derivative to zero, we get,

\dfrac{d(R(p))}{dp} = 0\\\\-10p + 1550 = 0\\\\p = \dfrac{-1550}{-10} = 155

Again differentiation R(p), with respect to p, we get,

\dfrac{d^2(R(p))}{dp^2} = -10

At p = 155

\dfrac{d^2(R(p))}{dp^2} < 0

Thus by double derivative test, maxima occurs at p = 155 for R(p).

Thus, maximum revenue occurs when p = $155.

Maximum revenue

R(155) = -5(155)^2 + 1550(155) = 120125

Thus, maximum revenue is $120125 that occurs when the unit price is $155.

6 0
3 years ago
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