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There are 20 nickels and 16 quarters
<em><u>Solution:</u></em>
Let "n" be the number of nickels
Let "q" be the number of quarters
We know that,
1 nickel = 0.05 dollar
1 quarter = 0.25 dollar
<em><u>Gabby has a bag containing 36 nickels and quarters</u></em>
Therefore,
n + q = 36
n = 36 - q ------- eqn 1
<em><u>The total value of the coins is $5</u></em>
<em><u>Thus we frame a equation as:</u></em>
number of nickels x 1 nickel + number of quarters x 1 quarter = 5
0.05n + 0.25q = 5 ------- eqn 2
<em><u>Substitute eqn 1 in eqn 2</u></em>
0.05(36 - q) + 0.25q = 5
1.8 - 0.05q + 0.25q = 5
0.2q = 3.2
q = 16
<em><u>Substitute q = 16 in eqn 1</u></em>
n = 36 - 16
n = 20
Thus there are 20 nickels and 16 quarters
Answer:
209.55in²
Step-by-step explanation:
Find area of sector CADE
Radius =22 in
Angle=90°
Formula to apply is ;
Ф/360 × π × r² where
Ф=angle of sector, π=3.142 and r =radius of circle
Find area of triangle CAD where base length is 22 inches and height is 22 inches
Area of triangle formula is;
1/2×b×h where b is base and h is height
Find area remaining
380.182-242=138.182in²
Find the area of sector CBDF
Radius=28in
Angle=60°
Formula to apply is ;
Ф/360 × π × r² where
Ф=angle of sector, π=3.142 and r =radius of circle
Area of triangle BDC
The formula to apply is
1/2×a×a×sinФ where a=28 inches and Ф=60°
Remaining area
410.55-339.48=71.075in²
Area created by overlapping circles
138.182+71.075=209.26in²