Answer:
We need a sample size of at least 719
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of
.
So it is z with a pvalue of
, so 
Now, find the margin of error M as such

In which
is the standard deviation of the population and n is the size of the sample.
How large a sample size is required to vary population mean within 0.30 seat of the sample mean with 95% confidence interval?
This is at least n, in which n is found when
. So






Rouding up
We need a sample size of at least 719
Answer:

Step-by-step explanation:
Since 1 hour contains 60 minutes, So 1 hour would by divided by 60
So, the required expression is,
=> 
Answer:
3*(5*x-7)-(15*x-21)=0
Step-by-step explanation:
3 • (5x - 7) - (15x - 21) = 0
Step 2 :
Equation at the end of step 2 :
0 = 0
Step 3 :
Equations which are always true :
Hi Malik.
2x+4>14 or -(2x+4)>14
solve each inequality individually
you get
x>5 or x<-9