Answer:
1.50
Step-by-step explanation:
8 x 1.50=12
25-12=13
13-4=9
9/6=1.5
Only x-intercept because if you want to know about x-intercepts so y will be zero (y=0)
then 0 =4x^2 -12x + 9
0=(2x-3)(2x-3)
0=2x-3
so x=3/2 that is x-intercept
The solution depends on the value of
![k](https://tex.z-dn.net/?f=k)
. To make things simple, assume
![k>0](https://tex.z-dn.net/?f=k%3E0)
. The homogeneous part of the equation is
![\dfrac{\mathrm d^2y}{\mathrm dx^2}-16ky=0](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmathrm%20d%5E2y%7D%7B%5Cmathrm%20dx%5E2%7D-16ky%3D0)
and has characteristic equation
![r^2-16k=0\implies r=\pm4\sqrt k](https://tex.z-dn.net/?f=r%5E2-16k%3D0%5Cimplies%20r%3D%5Cpm4%5Csqrt%20k)
which admits the characteristic solution
![y_c=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}](https://tex.z-dn.net/?f=y_c%3DC_1e%5E%7B-4%5Csqrt%20kx%7D%2BC_2e%5E%7B4%5Csqrt%20kx%7D)
.
For the solution to the nonhomogeneous equation, a reasonable guess for the particular solution might be
![y_p=ae^{4x}+be^x](https://tex.z-dn.net/?f=y_p%3Dae%5E%7B4x%7D%2Bbe%5Ex)
. Then
![\dfrac{\mathrm d^2y_p}{\mathrm dx^2}=16ae^{4x}+be^x](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmathrm%20d%5E2y_p%7D%7B%5Cmathrm%20dx%5E2%7D%3D16ae%5E%7B4x%7D%2Bbe%5Ex)
So you have
![16ae^{4x}+be^x-16k(ae^{4x}+be^x)=9.6e^{4x}+30e^x](https://tex.z-dn.net/?f=16ae%5E%7B4x%7D%2Bbe%5Ex-16k%28ae%5E%7B4x%7D%2Bbe%5Ex%29%3D9.6e%5E%7B4x%7D%2B30e%5Ex)
![(16a-16ka)e^{4x}+(b-16kb)e^x=9.6e^{4x}+30e^x](https://tex.z-dn.net/?f=%2816a-16ka%29e%5E%7B4x%7D%2B%28b-16kb%29e%5Ex%3D9.6e%5E%7B4x%7D%2B30e%5Ex)
This means
![16a(1-k)=9.6\implies a=\dfrac3{5(1-k)}](https://tex.z-dn.net/?f=16a%281-k%29%3D9.6%5Cimplies%20a%3D%5Cdfrac3%7B5%281-k%29%7D)
![b(1-16k)=30\implies b=\dfrac{30}{1-16k}](https://tex.z-dn.net/?f=b%281-16k%29%3D30%5Cimplies%20b%3D%5Cdfrac%7B30%7D%7B1-16k%7D)
and so the general solution would be
Answer: 112 inches.
Step-by-step explanation:
You know that the width of the rectangular piece of wood is 4 inches and the width of the strip ribbon is 1/4 inches.
Then, let be "n" the number of strips ribbon that Laura needs to cover the width of the rectangular piece of wood (Assuming that she will cover the wood in the form shown in the figure attached). This is:
![n=\frac{4in}{\frac{1}{4}in}\\\\n=16](https://tex.z-dn.net/?f=n%3D%5Cfrac%7B4in%7D%7B%5Cfrac%7B1%7D%7B4%7Din%7D%5C%5C%5C%5Cn%3D16)
To find the lenght of ribbon that Laura needs to conver the wood, you must multiply the number of strips ribbon "n" by the lenght of the rectangular piece of wood, then you get:
![lenght=(16)(7in)\\lenght=112in](https://tex.z-dn.net/?f=lenght%3D%2816%29%287in%29%5C%5Clenght%3D112in)