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3 years ago

Please Help me Due today

Mathematics

1 answer:

Helen [10]3 years ago

3 0

Answer:

Strong positive correlation

Step-by-step explanation:

The given scatterplot, where the data points are sloping upward:

The stronger the association of the two variables, the closer the Pearson correlation coefficient, <em>r</em>, will be to either +1 or -1 depending on whether the relationship is <em>positive</em> or <em>negative</em>, respectively.

If the value of the correlation coefficient is 0 < <em>r</em> < 1 then there is a positive linear trend and the data points are scattered around the line of best fit; the smaller the absolute value of <em>r, </em>the less well the data can be visualized by a single linear relationship. The closer the value of r to 0 the greater the variation around the line of best fit.

In the attached screenshot, where I've drawn a line across the graph: it shows that the data points are clustered around the line. It is easier to estimate that the value of <em>r </em>is closer to 1, which implies a strong positive relationship between two variables. My estimate is that <em>r</em> = 0.8.

Therefore, the correct answer is Strong Positive association.

Please mark my answers as the Brainliest, if you find this helpful :)

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Geometric mean between 9 and 36

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3 years ago

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Veseljchak [2.6K]

Answer:

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3 years ago

Triangle P Q R is shown. The length of P Q is 20 and the length of P R is 12. Angle Q P R is 68 degrees and angle P Q R is 36 de

Tom [10]

Answer:

<h2> 112.3 square units</h2>

Step-by-step explanation:

Find the sketch of the triangle attached.

Area of the triangle = $\frac{1}{2}|PQ| |PR| sinQPR$

Given PQ = 20, PR = 12 and ∠QPR = 68°

Area of the triangle = 1/2 * 20 * 12 * sin68°

Area of the triangle = 120sin68°

Area of the triangle = 112.26 square units

Area of the triangle ≈ 112.3 square units (to the nearest tenth of a square unit)

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3 years ago

Read 2 more answers

Which values for h and k are used to write the function f of x = x squared 12 x 6 in vertex form?

Nesterboy [21]

The values of h and k when f(x) = x^2 + 12x + 6 is in vertex form is -6 and -30

<h3>How to rewrite in vertex form?</h3>

The equation is given as:

f(x) = x^2 + 12x + 6

Rewrite as:

x^2 + 12x + 6 = 0

Subtract 6 from both sides

x^2 + 12x = -6

Take the coefficient of x

k = 12

Divide by 2

k/2 = 6

Square both sides

(k/2)^2 = 36

Add 36 to both sides of x^2 + 12x = -6

x^2 + 12x + 36= -6 + 36

Evaluate the sum

x^2 + 12x + 36= 30

Express as perfect square

(x + 6)^2 = 30

Subtract 30 from both sides

(x + 6)^2 -30 = 0

So, the equation f(x) = x^2 + 12x + 6 becomes

f(x) = (x + 6)^2 -30

A quadratic equation in vertex form is represented as:

f(x) = a(x - h)^2 + k

Where:

Vertex = (h,k)

By comparison, we have:

(h,k) = (-6,-30)

Hence, the values of h and k when f(x) = x^2 + 12x + 6 is in vertex form is -6 and -30

Read more about quadratic functions at:

brainly.com/question/1214333

#SPJ1

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2 years ago

Graph Y = -1/2x-6<br> Please help me out! I will mark answer brainiest if you do...

elena55 [62]

Y = -1/2x - 6......u have a slope of -1/2....u have a y int of -6 or (0,-6)

the x int can be found by subbing in 0 for y and solving for x
0 = -1/2x - 6
1/2x = -6
x = -6 * 2
x = -12.....so ur x int is -12 or (-12,0)

so go ahead and plot ur intercepts.....(0,-6) and (-12,0)...well...u cant really plot ur x axis because ur graph is not big enough....so start at (0,-6)...and I know the slope is -1/2....and u would usually start at (-12,0)...but that is not on the graph....so start at (0.-6)....and go up 1 and to the left 2, plot that point....then up 1 and to the left 2...plot that point......u would eventually cross the x axis at (-12,0).

or u could just go to desmos....its a graphing calculator...and see for urself

4 0

3 years ago