Answer:
a
Step-by-step explanation:
Answer:
<u>Given :</u>
length offshore = CS=√(1+X^2)
Cable charged = 5000√(1+X^2)
onshore length = 4-X
laying cost = 3000(4-X)
total cost:
C=5000√(1+X^2) +3000(4-X)
DC/DX
= [5000*(0.5)*2X/{√(1+X^2)}]-3000=0... for optimum
5000X=3000√(1+X^2)
25X^2=3+3X^2
22X^2=3
X=√(3/22)
= 0.3693 miles
So, it would be laid offshore to S in a manner that
BS=X=0.3693 miles
Onshore=4-0.3693
=3.6307 miles
Answer:
Population after n years = Present Population =(1+
100
r
)
n
Population after 2 years =50000(1+
100
5
)
2
=50000(
100
105
)
2
=50000×
100
105
×
100
105
=5×105×105=55125
Step-by-step explanation:
Answer: $249,300
Step-by-step explanation:
The exact formula would be if I think this is right
PV = PMT(1-(1+r)^-n)/r with r & n adjusted for periodicity
= 1400(1-(1+.054/12)^-360)/(.054/12)
= $249,318.47
which you can round off to, say, $249,300 <------
note:
counterchechecked with a financial calculator
16, 18, 23, 25, 26, 34, 37, 37, 40, 41, 46
37 is the upper quartile value
