Can't take the square root of a negative so find a domain where it takes squaer root of 0 wich is allowed hold a sec
there
the denomenator can't be 0 so x cannot be 3, it has to be greater
Answer:
$17.12
Step-by-step explanation:
First let's find the normal cost with tax
7/100*19=133/100=$1.33
$19+$1.33=$20.33
Now we find the cost with tax for the Valentine's Day price
7/100*35=$2.45
$35+$2.45=$37.45
Now we subtract the normal cost from the Valentine's Day price
$37.45-$20.33=$17.12
Answer: -11
Step-by-step explanation:
Since 
and 
, we can rewrite the right side of the equation as
Using the identity 
, we can subtract 
from either side to obtain the identity 
substituting that into our previous expression, the right side of our equation simply becomes
We can now write our whole equation as
Adding 2 to both sides:
dividing both sides by 3:
When 0 ≤ x ≤ π, tan x can only be equal to 1 when sin x = cos x, which happens at x = π/4, and it can only be equal to -1 when -sin x = cos x, which happens at x = 3π/4
Answer:
13/21
Step-by-step explanation:
Make 6 1/2 and 10 1/2 and improper fraction
6 1/2=13/2
10 1/2=21/2
K.C.F
Keep 13/2
Change the division symbol to multiplication
Flip 21/2 to 2/21
then multiply across
13*2=26
21*2=42
so the fraction is 26/42 and then simplify the fraction
13/21
