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2 years ago

Wanna get 20 points then follow me

Mathematics

1 answer:

crimeas [40]2 years ago

6 0

Answer:

Is that true? I will follow you

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I need the equation for this ASAP!

Sindrei [870]

Answer:

5.714 liters of the 5% solution and 4.286 of the 40%.

Step-by-step explanation:

Let x be the volume of 40% solution and y = volume of the 5% solution.

x + y = 10

0.40x + 0.05y = 0.20(x + y)

From the first equation x = 10 -y so we have:

0.40(10 - y) + 0.05y = 0.20( 10 - y + y)

4 - 0.40y + 0.05y = 2

-0.35y = -2

y = 5.714 liters of the 5%.

and x = 10 - 5.714 = 4.286 liters of the 40% solution.

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

William buys two bags of peaches and three bags of apricots for 17 dollars. Sylvia buys four bags of peaches and two bags of apr

crimeas [40]

One pound of peaches is $4.

8 0

3 years ago

The radius of a circle 6 cm what is the circles area?

dolphi86 [110]

Answer:

113.04 cm

Step-by-step explanation:

We know the formula to find the area of a circle is

$A= pi(r^{2})$

And we are told to use 3.14 instead of pi so what we have now is,

$A=3.14(r^{2})$

We are also told the radius, r, is 6. So our equation now looks like this,

$A=3.14(6^{2})\\\\6^{2}$ is the same as 36, because 6x6 is 36.

Now we have,

$A=3.14(36)$

Which equals 113.04 and that is the area!

Hope that helps and have a great day!

7 0

3 years ago

What is 4/7÷2/3? please help me with this

SIZIF [17.4K]

Answer:

Hi! The correct answer is 8/21!

Step-by-step explanation:

<em><u>~Simplify the expression~</u></em>

4 0

3 years ago

Read 2 more answers

1) Use power series to find the series solution to the differential equation y'+2y = 0 PLEASE SHOW ALL YOUR WORK, OR RISK LOSING

iogann1982 [59]

$y=\displaystyle\sum_{n=0}^\infty a_nx^n$

then

$y'=\displaystyle\sum_{n=1}^\infty na_nx^{n-1}=\sum_{n=0}^\infty(n+1)a_{n+1}x^n$

The ODE in terms of these series is

$\displaystyle\sum_{n=0}^\infty(n+1)a_{n+1}x^n+2\sum_{n=0}^\infty a_nx^n=0$

$\displaystyle\sum_{n=0}^\infty\bigg(a_{n+1}+2a_n\bigg)x^n=0$

$\implies\begin{cases}a_0=y(0)\\(n+1)a_{n+1}=-2a_n&\text{for }n\ge0\end{cases}$

We can solve the recurrence exactly by substitution:

$a_{n+1}=-\dfrac2{n+1}a_n=\dfrac{2^2}{(n+1)n}a_{n-1}=-\dfrac{2^3}{(n+1)n(n-1)}a_{n-2}=\cdots=\dfrac{(-2)^{n+1}}{(n+1)!}a_0$

$\implies a_n=\dfrac{(-2)^n}{n!}a_0$

So the ODE has solution

$y(x)=\displaystyle a_0\sum_{n=0}^\infty\frac{(-2x)^n}{n!}$

which you may recognize as the power series of the exponential function. Then

$\boxed{y(x)=a_0e^{-2x}}$

7 0

3 years ago

Wanna get 20 points then follow me​

Wanna get 20 points then follow me