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3 years ago

Simplify 4+9 X 2 + 3 - 1

Mathematics

1 answer:

kompoz [17]3 years ago

3 0

$\\ \sf\longmapsto 4+9(2)+3-1$

tex]\\ \sf\longmapsto 13(2)+2[/tex]

tex]\\ \sf\longmapsto 26+2[/tex]

tex]\\ \sf\longmapsto 28[/tex]

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3 years ago

In an isosceles trapezoid the length of a diagonal is 25 cm and the length of an altitude is 15 cm. Find the area of the trapezo

andreev551 [17]

Answer:

The area of the trapezoid is $525\ cm^{2}$

Step-by-step explanation:

we know that

The area of a isosceles trapezoid is equal to the area of two isosceles right triangles plus the area of a rectangle

step 1

<em>Find the area of the isosceles right triangle</em>

Remember that

In a isosceles right triangle the height is equal to the base of the triangle

we have

$h=15\ cm$

$b=15\ cm$

The area is equal to

$A=\frac{1}{2}(b)(h)$

substitute the values

$A=\frac{1}{2}(15)(15)=112.5\ cm^{2}$

step 2

Find the area of the rectangle

The area of the rectangle is equal to

$A=LW$

we have

$W=15\ cm$ -----> is the height of the trapezoid

$d=25\ cm$ -----> the diagonal of the rectangle

Applying the Pythagoras Theorem

$25^{2}=L^{2}+15^{2}\\L^{2}=25^{2}-15^{2} \\ L^{2} =400\\L=20\ cm$

The area of the rectangle is

$A=(20)(15)=300\ cm^{2}$

step 3

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$A=2(112.5\ cm^{2})+300\ cm^{2}=525\ cm^{2}$

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4 years ago

Read 2 more answers

Simplify 4+9 X 2 + 3 - 1​

Simplify 4+9 X 2 + 3 - 1