All categories

3 years ago

I don’t understand how to do 1 a.

Mathematics

1 answer:

nikitadnepr [17]3 years ago

3 0

a. 6 x 5 = 30

b. 5.6 x 5 = 28

a. 20 devided by 5 = 5.6

b. 36 devided by 5 = 7.2 (i dont know, that sounds like a pretty tall person to me)

You might be interested in

Find the distance between the points (−5,2) and (9.2)

forsale [732]

Step-by-step explanation:

Formula Used

By distance formula,

d (A,B)=√[(x₁ - x₂)² + (y₁ - y₂)²]

$\sf \longmapsto \: D = √(x2-x1)²+(y2-y1)²$

$\sf \longmapsto= √(9+5)²+(2-2)²$

$\sf \longmapsto= = √14²+09$

$\sf \red \longmapsto \boxed{= 14}$

4 0

2 years ago

Sin5A/SinA-cos5A/cosA=4cos2A

irina1246 [14]

Answer:

See Explanation

Step-by-step explanation:

$\frac{ \sin5A}{\sin A} - \frac{ \cos5A}{\cos A} = 4\cos2A \\ \\ LHS = \frac{ \sin5A}{\sin A} - \frac{ \cos5A}{\cos A} \\ \\ = \frac{ \sin5A \:\cos A - \cos5A \: \sin A}{\sin A \:\cos A } \\ \\ = \frac{ \sin(5A -A )}{\sin A \:\cos A} \\ \\ = \frac{ \sin 4A}{\sin A \:\cos A} \\ \\ = \frac{ 2\sin 2A \: \cos 2A}{\sin A \:\cos A} \\ \\ = \frac{ 2 \times 2\sin A \: \cos A \: \cos 2A}{\sin A \:\cos A} \\ \\ = \frac{ 4\sin A \: \cos A \: \cos 2A}{\sin A \:\cos A} \\ \\ =4\cos 2A \\ \\ = RHS \\ \\ thus \\ \\ \frac{ \sin5A}{\sin A} - \frac{ \cos5A}{\cos A} = 4\cos2A \\ \\ hence \: proved$

5 0

3 years ago

When finding the intersection of two lines from both Algebra I and Geometry, you first "set the linear equations equal" to each

Step2247 [10]

Answer:

hola quetall cm eatanfufuguvuggugdyfyxjcjv

5 0

2 years ago

Look at the coordinate graph.

dezoksy [38]

Answer:

B = (5,4), C = (-5, -4), D = (5, -4), A = (-5, 4)

Step-by-step explanation:

look at x axis first (horizontal), then y axis (vertical)

8 0

2 years ago

3 3/4 + 1 2/5 answer

Nonamiya [84]

The answer is 3 3/20

4 0

2 years ago