Tgα = tan(α) = sqrt(2)/1 = opposite/ adjacent
opposite = sqrt(2)
adjacent = 1
hypotenuse = sqrt(opposite^2 + adjacent^2)
= sqrt(sqrt(2)^2 + 1^2) = sqrt(3)
sin(α) = opposite/hypotenuse
= sqrt(2)/sqrt(3)
cos(α) = adjacent/hypotenuse
= 1/sqrt(3)
now we can calculate the value of
5sin²α+3cos²α / 3sin²α-5cos²α
... do the math
Answer:
The largest possible area of the deck is 87.11 m² with dimensions;
Width = 9.33 m
Breadth = 9.33 m
Step-by-step explanation:
The area of a given dimension increases as the dimension covers more equidistant dimension from the center, which gives the quadrilateral with largest dimension being that of a square
Given that the railings will be placed on three sides only and the third side will cornered or left open, such that the given length of railing can be shared into three rather than four to increase the area
The length of the given railing = 28 m
The sides of the formed square area by sharing the railing into three while the fourth side is left open are then equal to 28/3 each
The area of a square of side s = s²
The largest possible area of the deck = (28/3)² = 784/9 = 87.11 m² with dimensions;
Width = 28/3 m = 9.33 m
Breadth = 28/3 m = 9.33 m.
Answer:
y = 8
Step-by-step explanation:
Step 1: Write equation
3 - 5y = -37
Step 2: Subtract 3 on both sides
-5y = -40
Step 3: Divide both sides by -5
y = 8
