Answer:QB = 1/2 QE
QC = CF
DE = 2AB
Step-by-step explanation: hope it works
Make sure the question is stated clearly
B should be correct
Hope that helped
<span>The sum of two numbers is 48.
a + b = 48
;
If one third of one number is 5 greater than one sixth of another number,
a = b + 5
multiply both sides by 6, cancel the fractions
2a = b + 30
2a - b = 30
</span><span>use elimination to solve this
a + b = 48
2a - b =30
-------------Addition eliminates b, find a
3a = 78
a =
a = 26
then
26 + b = 48
b = 48 - 26
b = 22</span>
The sequence is given by (n+5)²
For n=100:
(100+5)² = 105² = 11025
