<em>Answer:</em>
<em />
<em>x³ + x² - 6x = 0</em>
<em>x(x² + x - 6) = 0</em>
<em>x(x² + 3x - 2x - 6) = 0</em>
<em>x[x(x + 3) - 2(x + 3)] = 0</em>
<em>x(x - 2)(x + 3) = 0</em>
<em>x₁ = 0</em>
<em>x - 2 = 0 => x₂ = 2</em>
<em>x + 3 = 0 => x₃ = - 3</em>
Answer:
the answer is yes it will
I would try using a table. It might work better.
Answer:
6
Step-by-step explanation:
f(x) = 2(x-5)
f(8) = 2(8-5)
- parentheses comes first so, 8-5 = 3
- 2(3), so multiply and the final answer is 6
f(8) = 6
