What is the fourth term of an arithmetic sequence whose first term is 23 and whose seventh term is 5?
1 answer:
We have that the fourth term of an arithmetic sequence is
a_4=14
Option C
From the question we are told
What is the fourth term of an arithmetic sequence whose first term is 23 and whose seventh term is 5?
A) 78
B) 32
C) 14
(Explain your work)
Generally the equation for the arithmetic sequence is mathematically given as
Therefore
For seventh term
Therefore
For Fourth term
a_4=14
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Answer:
Step-by-step explanation:
We are given an isosceles triangle. We need to remember the important rule that the base angles are equal. In this question we need to find the value of 'x' using a perpendicular height of 3 and a base length of 4. In this question we can half the triangle in half to help us find the value of x. Also we need to use Pythagoras theorem to help us find 'x'. Pythagoras states that a² + b² = c² so we want to find the hypotenuse of the triangle. If we half the triangle we get 2 triangle both with a base length of 2 and a perpendicular height of 3 so,
⇒ State Pythagoras theorem
→ a² + b² = c²
⇒ Substitute in the values
→ 3² + 2² = c²
⇒ Simplify
→ 9 + 4 = c²
⇒ Simplify further
→ 13 = c²
⇒ Square root both sides to find the value of 'c'
→ = c
The value of x is the square root of 13