Always, sometimes, or never true?

Solve the above questions don't spam

Bas_tet [7]

Answer:

10th question ka answer hai OK

7 0

3 years ago

8. Part A: Find the value of x.

DiKsa [7]

Answer:

B.x=3

Part B. 15 units

3 0

3 years ago

Read 2 more answers

Quaker oatmeal is a very popular breakfast cereal .If susan wrapped the entire container with out any overlapping paper what is

mylen [45]

Answer:

263.76

Step-by-step explanation:

To answer this question, we need to know the equation for surface area of a cylinder which can be given as Surface Area=2*pi* $R^{2}$ +2*pi*R*H, where R is the radius of the cylinder (also can be calculated as Diameter/2=6/2=3) and H is the height of the cylinder which is given as 11. Considering pi=3.14, the surface area of the cylinder can now be calculated as 2*3.14* $3^{2}$ +2*3.14*3*11=263.76.

3 0

3 years ago

A tank initially has 300 gallons of a solution that contains 50 lb. of dissolved salt. A brine solution with a concentration of

belka [17]

Let s(t) be the amount of salt in the tank at time t. Then s(0) = 50 lb.

Salt flows into the tank at a rate of

(2 gal/min) (6 lb/gal) = 12 lb/min

and flows out at a rate of

(2 gal/min) (s(t)/300 lb/gal) = s(t)/150 lb/min

so that the net rate at which salt is exchanged through the tank is

ds(t)/dt = 12 - s(t)/150 … (lb/min)

Solve for s(t). The DE is separable, so we have

ds/dt = 12 - s/150

150 ds/dt = 1800 - s

150/(1800 - s) ds = dt

Integrate both sides to get

-150 ln|1800 - s| = t + C

Solve for s :

ln|1800 - s| = -t/150 + C

1800 - s = exp(-t/150 + C )

1800 - s = C exp(-t/150)

s = 1800 - C exp(-t/150)

Now given that s(0) = 50, we solve for C :

50 = 1800 - C exp(-0/150)

50 = 1800 - C

C = 1750

Then the amount of salt in the tank at any time t ≥ 0 is

s(t) = 1800 - 1750 exp(-t/150)

To find the time it takes for the tank to hold 100 lb of salt, solve for t in

100 = 1800 - 1750 exp(-t/150)

1700 = 1750 exp(-t/150)

34/35 = exp(-t/150)

ln(34/35) = -t/150

t = -150 ln(34/35) ≈ 4.348

So it would take approximately 4.348 minutes.

By the way, we didn't have to solve for s(t), we could have instead stopped with

-150 ln|1800 - s| = t + C

Solve for C - this C is not the same as the one we found using the other method. s(0) = 50, so

-150 ln|1800 - 50| = 0 + C

C = -150 ln|1750|

==> t = 150 ln(1750) - 150 ln|1800 - s|

Then s(t) = 100 lb when

t = 150 ln(1750) - 150 ln(1700)

t = 150 ln(1750/1700)

t = 150 ln(35/34)

t ≈ 4.348

5 0

3 years ago

the uniform distribution over the interval 8.5 to 11.5 gallons per minute. Find the probability that between 9.0 gallons and 10.

Tema [17]

Answer: 1/3

Step-by-step explanation:

Here is the complete question:

machine is set to pump cleanser into a process at the rate of 9 gallons per minute. Upon inspection, it is learned that the machine actually pumps cleanser at a rate described by the uniform distribution over the interval 8.5 to 11.5 gallons per minute. Find the probability that between 9.0 gallons and 10.0 gallons are pumped during a randomly selected minute.

The Probability of the above question will be calculated as:

= (10-9) / (11.5 - 8.5)

= 1/3

The above is the easier way to solve this

3 0

3 years ago