Find four consecutive integers whose sum is 114.

1 answer:

7 0

4 consecutive integers : (x), (x + 1), (x + 2), (x + 3)

x + x + 1 + x + 2 + x + 3 = 114...combine like terms
4x + 6 = 114....subtract 6 from both sides
4x = 114 - 6
4x = 108...divide both sides by 4
x = 108/4
x = 27

x + 1 = 27 + 1 = 28
x + 2 = 27 + 2 = 29
x + 3 = 27 + 3 = 30

so ur 4 numbers are : 27, 28, 29, 30

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