the first attachment is the problem factored
hope this helps
the other attchments are things that i can relate to
The sum of x^2−3xy−y^2 and 2x^2+5xy−4y^2:
x^2−3xy−y^2 + 2x^2+5xy−4y^2
= 3x^2 + 2xy - 5y^2
From 6x^2−7xy+8y^2 subtract the sum of x^2−3xy−y^2 and 2x^2+5xy−4y^2:
6x^2−7xy+8y^2 - (3x^2 + 2xy - 5y^2)
= 6x^2−7xy+8y^2 - 3x^2 - 2xy + 5y^2
= 3x^2−9xy + 13y^2
Answer
3x^2−9xy + 13y^2
In the second step, I rewrote 8 as 2*4. Then after that I regrouped terms so that the (3*2) can pair up together. This of course turns into 6. After that point, we have 6, 4 and x multiplied together as the base.
The last step uses the rule that 
, in other words, we apply the exponent d to each term inside the parenthesis. Each term inside gets its own exponent.
An example: 
Answer:
3
Step-by-step explanation:
because she uses beads
so the number of beads go down
The methods for comparing rational numbers include:
- Cross-multiply and compare the products.
- Convert both fractions to fractions with a common denominator.
- Turn both fractions into decimals by dividing.
<h3>What is a rational number?</h3>
It should be noted that a rational number is a number that is expressed as the ratio of two integers, where the denominator should not be equal to zero.
Rational numbers are terminating decimals while irrational numbers are non-terminating and non-recurring.
Learn more about numbers on:
brainly.com/question/24368848
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