Answer:
Find a polynomial function whose graph passes through (6,13), (9,-11), (0,5)
1 Answers
Assuming a quadratic, we have that
y = ax^2 + bx + c
Since (0,5) is on the graph, c =5
And we have the remaining system
a(9)^2 + b(9) + 5 = -11
a(6)^2 + b(6) + 5 = 13 simplify
81a + 9b = -16 multiply through by 6 ⇒ 486a + 54b = - 96 (1)
36a + 6b = 8 multiply through by -9 ⇒ -324a -54b = -72 (2)
Add (1) and (2)
162a = -168
a = -28/27
To find b we have
36 (-28/27) + 6b = 8
-112/3 + 6b = 8
⇒ b = 68/9
The function is
y = - (28/27)x^2 + (68/9)x + 5
First, she distributed
Which gave her
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hope this helps if you have any questions please pm me :)
Answer:
The answer to your question is 50 inches
Step-by-step explanation:
Data
Area = 200 in²
diagonal 1 = 8 in
diagonal 2 = ?
Formula
Area = (diagonal 1 x diagonal 2) / 2
Solve for diagonal 2
diagonal 2 = 2 x Area 2 / diagonal 1
-Substitution
diagonal 2 = 2 x 200 / 8
-Simplification
diagonal 2 = 400 / 8
-Result
diagonal 2 = 50 in
Circumference = 2 pi r
11304 = 2 x 22/7 x r
11304 x 7/2x22 =r = 1798.36
Answer:
24
Step-by-step explanation:
(72/-9) / (-1/3)
72/-9) x (-3/1)
(72)*(-3) = - 216/ -9
= 24
