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Bingel [31]
3 years ago
7

David bought a chain of fast food restaurants that operated 200 stores in 2009. The number of restaurants has grown at a rate of

12% annually
Mathematics
1 answer:
Alina [70]3 years ago
5 0

Complete Question

David bought a chain of fast food restaurants that operated 200 stores in 2009. The number of restaurants has grown at a rate of 12% annually.how many stores does the restaurant operate in 2020?

Answer:

N_{11} \approx 749

Step-by-step explanation:

From the question we are told that:

Number of Fast Food Restaurants P=200

Number of years t=11yrs

Rate r=12%

Generally the equation for the Number of restaurant in operation in 2020 is mathematically given by

 N(t)=Pe^{rt}

Therefore

For t=11

 N_{11}=200*e^{0.12*11}

 N_{11}=748.7

 N_{11} \approx 749

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-2 units, 6 units = (5,5)

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3 years ago
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Alex73 [517]

Answer:

1) Option c) is correct ie., 5 real and o non-real

2) Option b) is correct ie., (4, \frac{1}{2}, \frac{1}{2}, 2,2)

Step-by-step explanation:

Given polynomial function is f(x)=x^5-3x^3-2

To find zeros equate f(x) to zero ie.,  f(x)=0

x^5-3x^3-2=0

By synthetic division

     |   1     0    -3      0      -2

-1  |   0    -1      1      2      2

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Therefore x=-1 is a zero

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x^2 -2 =0

x=\pm\sqrt{2}

x=\sqrt{2} and

x=\sqrt{-2}

Option c) is correct ie., 5 real and o non-real

2) Given polynomial function is f(x)=(x-4)(2x-1)^2(x-2)^2

To find zeros equate f(x) to zero ie.,  f(x)=0

                                                            (x-4)(2x-1)^2(x-2)^2=0

(x-4)=0 (or) (2x-1)^2=0 or (x-2)^2=0

Therefore x=4, x=\frac{1}{2} of multiplicity of 2 and x=2 multiplicity of 2

Option b) is correct ie., (4, \frac{1}{2}, \frac{1}{2}, 2,2)

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