The athletic director of a college would like to reduce the number of injuries of her athletes. She believes that the ideal amou
nt of sleep for college students is 8 hours per night. During the school year, all athletes tracked how much they slept each night, and their average time slept was rounded to the nearest hour (6, 7, 8, or 9 hours). The coaches of all teams reported whether the athlete was injured throughout the year.
The Athletic director read that college students need 8 hours of sleep each night and believes that this group will have the least chance of injury. Her hypothesis is Athletes who sleep 8 hours each night will have the least chance of injury.
Using the information above, write a conclusion for this experiment. Is the hypothesis supported by the data? Explain why or why not using evidence to support your reasoning. Write your answer in complete sentences.
The Athletic director read that college students need 8 hours of sleep each night and believes that this group will have the least chance of injury. Her hypothesis is Athletes who sleep 8 hours each night will have the least chance of injury.
Using the information above, write a conclusion for this experiment. Is the hypothesis supported by the data? Explain why or why not using evidence to support your reasoning. Write your answer in complete sentences.
1 answer:
You might be interested in
Answer and Explanation:
Given : Five males with an X-linked genetic disorder have one child each. The random variable x is the number of children among the five who inherit the X-linked genetic disorder.
To find :
a. Does the table show a probability distribution?
b. Find the mean and standard deviation of the random variable x.
Solution :
a) To determine that table shows a probability distribution we add up all six probabilities if the sum is 1 then it is a valid distribution.
Yes it is a probability distribution.
b) First we create the table as per requirements,
x P(x) xP(x) x² x²P(x)
0 0.029 0 0 0
1 0.147 0.147 1 0.147
2 0.324 0.648 4 1.296
3 0.324 0.972 9 2.916
4 0.147 0.588 16 2.352
5 0.029 0.145 25 0.725
∑P(x)=1 ∑xP(x)=2.5 ∑x²P(x)=7.436
The mean of the random variable is
The standard deviation of the random sample is
Therefore, The mean is 2.5 and the standard deviation is 1.08.