HOW CAN YOU MAKE 7,5,6,AND 3 EQUAL 75 USING PARENTHESIS.

URGET PLEASE HELP QUICKLY

alexdok [17]

Answer: -0.5.

Step-by-step explanation:

The constant of variation k for the direct variation is given by:-

$k= \dfrac{f(x_2)}{x_2}=\dfrac{f(x_1)}{x_1}$

The given table:

x f( x )

0 0

2 -1

4 -2

7 -3.5

Then,

$k=\dfrac{-1}{2}=\dfrac{-2}{4}=\dfrac{7}{-3.5}=-0.5$

Hence, the constant of variation k for the direct variation is -0.5.

4 0

3 years ago

Pauline is building a fence around her vegetable garden, what length of fence will she need to build?

Nuetrik [128]

I FOUND YOUR COMPLETE QUESTION IN OTHER SOURCES.
SEE ATTACHED IMAGE.
First we look for the hypotenuse of both triangles.
Left triangle:
Sine (68.1) = (1.75) / (h)
h = (1.75) / Sine (68.1)
h = 1.886108667
h = 1.9m
Right triangle:
Sine (49.4) = (1.75) / (h)
h = (1.75) / Sine (49.4)
h = 2.304841475
h = 2.3m
Finally adding the perimeter:
P = 5 + 1.9 + 2.75 + 2.3
P = 11.95 m
Answer:
she will need to build 11.95 m of fence

6 0

3 years ago

Anyone know this cause my sister been lost for a day on this. I know it's nice t that hard to most of y'all but it's hard for he

IRINA_888 [86]

Answer: The book tax is $1.10 and the video game is $3.40 so i'll let you figure this out

tell your sister that the nae nae frog has blessed her with the answer

6 0

3 years ago

Vertical plane R intersects horizontal plane P. Points A, D, and B are on the line of the intersecting planes. Point F is on the

Ugo [173]

Answer:

1. lineDB

2.H

3,D

Step-by-step explanation:

edge 2020

Brainliest would be appreciated

7 0

3 years ago

Read 2 more answers

Let z denote a random variable that has a standard normal distribution. Determine each of the probabilities below. (Round all an

Gelneren [198K]

Answer:

(a) P (Z < 2.36) = 0.9909 (b) P (Z > 2.36) = 0.0091

(c) P (Z < -1.22) = 0.1112 (d) P (1.13 < Z > 3.35) = 0.1288

(e) P (-0.77< Z > -0.55) = 0.0705 (f) P (Z > 3) = 0.0014

(g) P (Z > -3.28) = 0.9995 (h) P (Z < 4.98) = 0.9999.

Step-by-step explanation:

Let us consider a random variable, $X \sim N (\mu, \sigma^{2})$ , then $Z=\frac{X-\mu}{\sigma}$ , is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, $Z \sim N (0, 1)$ .

In statistics, a standardized score is the number of standard deviations an observation or data point is above the mean. The z-scores are standardized scores.

The distribution of these z-scores is known as the standard normal distribution.

(a)

Compute the value of P (Z < 2.36) as follows:

P (Z < 2.36) = 0.99086

≈ 0.9909

Thus, the value of P (Z < 2.36) is 0.9909.

(b)

Compute the value of P (Z > 2.36) as follows:

P (Z > 2.36) = 1 - P (Z < 2.36)

= 1 - 0.99086

= 0.00914

≈ 0.0091

Thus, the value of P (Z > 2.36) is 0.0091.

(c)

Compute the value of P (Z < -1.22) as follows:

P (Z < -1.22) = 0.11123

≈ 0.1112

Thus, the value of P (Z < -1.22) is 0.1112.

(d)

Compute the value of P (1.13 < Z > 3.35) as follows:

P (1.13 < Z > 3.35) = P (Z < 3.35) - P (Z < 1.13)

= 0.99960 - 0.87076

= 0.12884

≈ 0.1288

Thus, the value of P (1.13 < Z > 3.35) is 0.1288.

(e)

Compute the value of P (-0.77< Z > -0.55) as follows:

P (-0.77< Z > -0.55) = P (Z < -0.55) - P (Z < -0.77)

= 0.29116 - 0.22065

= 0.07051

≈ 0.0705

Thus, the value of P (-0.77< Z > -0.55) is 0.0705.

(f)

Compute the value of P (Z > 3) as follows:

P (Z > 3) = 1 - P (Z < 3)

= 1 - 0.99865

= 0.00135

≈ 0.0014

Thus, the value of P (Z > 3) is 0.0014.

(g)

Compute the value of P (Z > -3.28) as follows:

P (Z > -3.28) = P (Z < 3.28)

= 0.99948

≈ 0.9995

Thus, the value of P (Z > -3.28) is 0.9995.

(h)

Compute the value of P (Z < 4.98) as follows:

P (Z < 4.98) = 0.99999

≈ 0.9999

Thus, the value of P (Z < 4.98) is 0.9999.

**Use the z-table for the probabilities.

3 0

3 years ago