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Semenov [28]
3 years ago
8

What is x+y=5 solved and graphed???? I need help, please!

Mathematics
2 answers:
grin007 [14]3 years ago
7 0

Answer:

The answer is y=5−x and to graph it on a graph it is (0.5) and (5.0)

Step-by-step explanation:

I took the quiz

Len [333]3 years ago
3 0
X+y=5 !!!!!!!!!!!!!!!
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What is the sum? 2x/x^2 + x-4/9x​
s2008m [1.1K]

Answer:(x² + 14x)/(9x²)

Step-by-step explanation:

Explanation:To do this calculatio process:The first term: 2x/x² = 2/x.Then: (2/x) + (x - 4)/(9x).We should common the denominator by multiplying the denominators of the two terms (9x)(x) = 9x² and dividing each denominator by the common denominator.So, it will be equal:[(2)(9x) + (x - 4)(x)]/9x² = (18x + x² - 4x)/9x² = (x² + 14 x)/9x².

4 0
3 years ago
Compose an expression that can model the first three terms of any arithmetic sequence in terms of just a and d. Type your answer
Mkey [24]

Answer:

First term: a

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Step-by-step explanation:

4 0
3 years ago
The question is in the image
Drupady [299]

Answer:

h(t) = -5*t^2 + 20*t  + 2

Step-by-step explanation:

First, we know that the motion equation of the ball will be quadratic, so we write the equation:

h(t) = a*t^2 + b*t + c

Now we need to work with the data in the table.

h(1) = 17

h(3) = 17

h(1) = h(2) = 17

Then we have a symmetry around:

(3 - 1)/2 + 1 = 2

Remember that the symmetry is around the vertex of the parabola, then we can conclude that the vertex of the parabola is the point:

(2, h(2)) = (2, 22)

Remember that for a quadratic equation:

y = a*x^2 + b*x + c

with a vertex (h, k)

we can rewrite our function as:

y = a*(x - h)^2 + k

So in this case, we can rewrite our function as:

h(t) = a*(t - 2)^2 + 22

To find the value of a, notice the first point in the table:

(0, 2)

then we have:

h(0) = 2 = a*(0 - 2)^2 + 22

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           2 - 22 = a*(4)

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Then our function is:

h(t) = -5*(t - 2)^2 + 22

Now we just expand it:

h(t) = -5*(t^2 - 4*t + 4) + 22

h(t) = -5*t^2 + 20*t  + 2

The correct option is the first one.

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25 anything raised to zero equals one
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Answer:

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