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Soloha48 [4]
3 years ago
7

Solve the equation for x :

Mathematics
1 answer:
fiasKO [112]3 years ago
5 0
X=8 my photo has the work done

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I need help pleasssss
Yakvenalex [24]

Answer:

  3)  16.2

Step-by-step explanation:

The supplement to the 115° angle on the right is 65°, the same as the angle at upper left. The vertical angles at C are the same measure, so this tells you that the two triangles FCB and ACD are similar by the AA similarity postulate. That being the case, corresponding sides are proportional:

  CB/CD = CF/CA

  CB = CD·CF/CA = 7.2·21.6/9.6

  CB = 16.2

_____

When given two "point-to-point" triangles like this, quite often there is some sort of similarity relationship involved. First, you need to figure out what it is; then you need to make use of it as needed to answer the question being asked.

4 0
3 years ago
1. Libby is calculating her net worth. Her
natulia [17]

Answer:

$119,703

Step-by-step explanation:

This question is easy, it is just $87,545 plus $32,158

5 0
3 years ago
Choose a true statement
34kurt

Answer:

A true statement

Step-by-step explanation:

WHAT R THE STATEMENTS

7 0
3 years ago
Read 2 more answers
I will give you brainiest just pls answer this question!!!
navik [9.2K]

Answer:

The correct unit price is $1.19 per pair of gloves. She made the mistake of dividing the total price by 3 instead of 3 dozen(which is 36).

Step-by-step explanation:

hope that helps!!!

3 0
3 years ago
Read 2 more answers
prove that the quadrilateral whose vertices are the points A(-1,1), B(-3,4), C(1,5) and D(3,2) is a parallelogram.
Vsevolod [243]

Answer:

Since \overrightarrow{AB} = \overrightarrow{DC} and \overrightarrow{AD} = \overrightarrow{BC}, then the quadrilateral ABCD is a parallelogram.

Step-by-step explanation:

First, we label each point of the quadrilateral with the help of a graphing tool. If the quadrilateral ABCD is a parallelogram, then \overrightarrow{AB} = \overrightarrow{DC} and \overrightarrow{AD} = \overrightarrow{BC}. If we know that A(x,y) =(-1, 1), B(x,y) =(-3,4), C(x,y) = (1,5) and D(x,y) = (3,2), then the measure of each vector is, respectively:

\overrightarrow{AB} = (-3,4)-(-1,1)

\overrightarrow{AB} = (-2, 3)

\overrightarrow{DC} = (1,5)-(3,2)

\overrightarrow{DC} = ( -2,3)

\overrightarrow{AD} = (3,2)-(-1,1)

\overrightarrow{AD} = (4, 1)

\overrightarrow{BC} = (1,5)-(-3,4)

\overrightarrow{BC} = (4, 1)

Since \overrightarrow{AB} = \overrightarrow{DC} and \overrightarrow{AD} = \overrightarrow{BC}, then the quadrilateral ABCD is a parallelogram.

7 0
3 years ago
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